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Answer:
Explanation:
Each of the following println statements will print the following values
ystem.out.println(floozy); // Problem 1: 97.4
System.out.println(theObj.gravy); //Problem 2: 107.43
System.out.println(xray[2]); //Problem 3: 100
System.out.println(s); //Problem 4: Hello
This is because out of all of the variables that the myMethod gives a value to, the only variable that is being saved back to the global variable in the main method is a[2]. The other variables are being saved as instance variables and not being returned. Therefore, when the println statements are called they target the local variables in the main method.
Answer:
Manufacturing
Explanation:
Planning. Data plots on all things and future plans as in if how much is bought what prices of stock you will have. Person could improve by taking courses in business planning.
Answer:
judging by the logo at the top it's a hyperx keyboard and looks to be the alloy core rgb... hope this helps!
Answer:
Constant
Explanation:
A default argument is a value provided in a function declaration that the compiler automatically assigns if the function caller does not provide a default value for the argument.
The value of a default argument must be constant.
The default value parameter must be a constant for compiling. Compiler does not accept dynamically calculated value against optional parameter. The reason behind this it is not certain that the dynamic value you provide would offer some valid value.
<u>Example:</u>
#include<iostream>
using namespace std;
/*A function with default arguments, it can be called upto 4 arguments*/
int sumnum(int x, int y, int z=0, int w=0)
{
return (x + y + z + w);
}
int main() //driver function
{
cout << sumnum(10, 15) << endl;
cout << sumnum(10, 15, 25) << endl;
cout << sumnum(10, 15, 25, 30) << endl;
return 0;
}
<u>Output</u>
<u>25
</u>
<u>50
</u>
<u>80</u>