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ASHA 777 [7]
3 years ago
9

Project planning output is :

Computers and Technology
1 answer:
-Dominant- [34]3 years ago
5 0

Answer:

A

Explanation:

The main output of Project palnning is project plan.

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Harmful programs used to disrupt computer operation, gather sensitive information, or gain unauthorized access to computer syste
Galina-37 [17]

Answer:

Malware

Explanation:

malware is used to disrupt computer operation, gather personal info, and or gain access to private computer systems.

6 0
3 years ago
What is the total running time of counting from 1 to n in binary if the time needed to add 1 to the current number i is proporti
KatRina [158]

The running time would be about 67minutes  

3 0
3 years ago
What is the foundational domain for business
mr Goodwill [35]

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hope this help

7 0
3 years ago
Jason, Samantha, Ravi, Sheila, and Ankit are preparing for an upcoming marathon. Each day of the week, they run a certain number
kolbaska11 [484]

Answer:

C++ program explained below for the problem

Explanation:

// UpComingMarathon.cpp : Defines the entry point for the console application.

//header files

#include "stdafx.h" //optional

#include <iostream>

#include <cstring>

#include <fstream>

#include <iomanip>

using namespace std;

//declare the gobal array of type double

double average[5];

//declare the function prototypes

void getData(ifstream& inf, string n[], double runData[][8], int count);

void calculateAverage(double runData[][8], int count);

void print(string n[], double runData[][8], int count);

int main()

{

   string names[5];

   double runningData[5][8];

   ifstream inputfile("input.txt");

   if(inputfile)

   {

        //call the method getData

        getData(inputfile, names, runningData, 5);

   }

   else

   {

        //error message

        cout<<"Sorry! Unable to open the file."<<endl;

        system("pause");

        return 0;

   }

   //close the file

   inputfile.close();

   //call the method calculateAverage to compute the

   //average miliage of each runner

   calculateAverage(runningData, 5);

   //call display the names and their weekly run rate and their averages

   print(names, runningData, 5);

   system("pause");

   return 0;

}

//definition of method getData that reads the data from the file and

//stores the names into array n and run data into runData array

//simultaneously.

void getData(ifstream& inf, string n[], double runData[][8], int count)

{  

   while(!inf.eof())

   {

        for(int i=0;i<count; i++)

        {

            inf>>n[i];

            for(int j=0;j<7;j++)

            {

                inf>>runData[i][j];

            }

        }

   }

}

//definition of method calculateAverage that comptes the total first

//then stores the value of average into the average array

void calculateAverage(double runData[][8], int count)

{

   double total;

   for(int i=0;i<count;i++)

   {

        total=0;

        for(int j=0;j<7;j++)

        {

            total+=runData[i][j];

        }        

        average[i]=total/7;      

   }

}

//definition of method print that prints the output

//in a tabular format

void print(string n[], double runData[][8], int count)

{

   cout<<setfill('=')<<setw(80)<<"=";

   cout<<setfill(' ');

   cout<<endl;

   cout<<"Name"<<setw(6)<<"";

   for(int i=0;i<7;i++)

        cout<<setw(7)<<"Day "<<(i+1);

   cout<<setw(12)<<"Average"<<endl;

   cout<<setfill('=')<<setw(80)<<"=";

   cout<<setfill(' ')<<endl;

   for(int i=0;i<count;i++)

   {

        cout<<n[i]<<setw(8)<<fixed<<"";

        for(int j=0;j<7; j++)

        {

            cout<<setprecision(2)<<fixed<<runData[i][j]<<setw(3)<<"";

        }

        cout<<setw(8)<<average[i];

        cout<<endl;

   }

   cout<<setfill('=')<<setw(80)<<"=";

   cout<<endl;

}

5 0
3 years ago
private int product(int n) { if(n &lt;= 1) return 1; else return n * product(n-2); } What is the output when product(6) is calle
sergeinik [125]

Answer:

48

Explanation:

In this code, there is a method i.e "product" of "int" type it means it returns the integer value. The description of the given code is given below

  • Initially when product(6) function is called the else block will be executed so return(6)*product(4).
  • As we saw that above product(4) is a recursion function " Function which calls itself again and again " . so again else block is executed now the value is return(6)*return(4) *return(2);

So it returns 48

7 0
3 years ago
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