Need help finding the area of the shaded region
1 answer:
Check the picture below, the assumption being that the 6ft line is perpendicular to the 18ft line and thus making a right-triangle.
now, if we just get the whole area of the containing parallelogram and then <u>get the area of the triangle and subtract it from that of the parallelogram's,</u> what's leftover is the area we didn't subtract, the shadead area.
You might be interested in
Answer:
∠B ≈ 30.0°
Step-by-step explanation:
The law of sines can be used to solve a triangle when two sides and an angle opposite one of them are given.
__
sin(B)/b = sin(C)/c
sin(B) = (b/c)sin(C) . . . . solve for sin(B)
sin(B) = (14/28)sin(91°) ≈ 0.49992385
The angle is found using the inverse sine function:
B = arcsin(0.49992384) ≈ 29.99496°
Rounded to tenths, the angle is ...
m∠B ≈ 30.0°
_____
<em>Additional comments</em>
Many triangle solver apps and web sites are available if all you want is an answer.
When using your calculator, be sure the angle mode is set to "degrees."
The Law of Sines can also be used to solve a triangle when two angles and one side are known.
