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Charra [1.4K]
2 years ago
7

If 3x^2+3y^2 = 42 and xy = -15, find the value of (x-y)^2

Mathematics
1 answer:
soldi70 [24.7K]2 years ago
7 0

Answer:

3x² + 3y² = 42

3 ( x² + y² ) = 42

x² + y² = 14

xy = -15 ( given )

(x-y)² = x² + y² - xy

14 - ( -15 )

14 + 15

<u>29</u>

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