Answer:
Step-by-step explanation:
The slope of the line needs to be determined first:
![m=\frac{-9+-5}{-12+-8}=\frac{-14}{-20}=\frac{7}{10}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-9%2B-5%7D%7B-12%2B-8%7D%3D%5Cfrac%7B-14%7D%7B-20%7D%3D%5Cfrac%7B7%7D%7B10%7D)
Now let's use that and one of the coordinates to write an equation in point-slope form:
![y-5=\frac{7}{10}(x-8)](https://tex.z-dn.net/?f=y-5%3D%5Cfrac%7B7%7D%7B10%7D%28x-8%29)
and, simplifying,
![y-5=\frac{7}{10}x-\frac{56}{10}](https://tex.z-dn.net/?f=y-5%3D%5Cfrac%7B7%7D%7B10%7Dx-%5Cfrac%7B56%7D%7B10%7D)
Now let's multiply everything by 10 to get rid of the fractions:
10y - 50 = 7x - 56
and
-7x + 10 y = -6
Apparently, they do not like to lead with negatives, which is not uncommon:
7x - 10y = 6
So his model is not correct.
Answer:
Your lowest point should be 26, and highest at 56, since that's your min and max value. Your median should be 40. Your Q1 should be 29, and Q2 should be 47.5
2 3/2 = 3 1/2 ( 3/2 = 1 1/2 + 2 = 3 1/2)
so area = 3 1/2 ^2
3 1/2 x 3 1/2 = 12 1/4
Area = 12 1/4
Answer:
Step-by-step explanation:
Given the coordinates E(13,8) and K(7,2), to get the length of the segment EK, we will use the formula for calculating the distance between two points expressed as:
D = √(x2-x1)²+(y2-y1)²
Given
x1 = 13, y1 = 8, x2 = 7, y2 = 2
EK =√(7-13)²+(2-8)²
EK = √(-6)²+(-6)²
EK = √36+36
EK = √72
EK = √36×√2
EK = 6√2
EK = 8.485
EK ≈8.5 (to the nearest tenth)
Hence the length of segment EK is 8.5
For the midpoint, the expression will be used
M(X,Y) = {(x1+x2)/2, (y1+y2)/2}
M(X,Y) = (13+7/2, 8+2/2)
M(X,Y) = (20/2, 10/2)
M(X,Y) = (10,5)
Hence the coordinates of its midpoint is (10,5)
Answer:
3
Step-by-step explanation:
First you combine like terms
3m + 5 = 14
now move the +5 over by subtraction
3m = 9
now divide by 3
m = 3