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2 years ago

14

What is the range of f(x) = 3x + 9?

1 answer:

Lera25 [3.4K]2 years ago

5 0

From the given options we can think that x is
in the exponent of 3.
So, the given function is actually f(x) = 3^x +9
Now, we need to find the range of given
function.
We can see that first term is and exponential
term 3^x and second term is 9
We know that 3^x will always be greater than
O.
Therefore, 3^x +9 would always be greater
than 9.
Therefore, range would be y>9.
So, the correct option is B) (y | y > 9}.

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8y-10=6y-2 help me please I don't get this

murzikaleks [220]

$8y-10=6y-2$

$8y-10=6y-2:y$ $| Solve \ for \ y|$

$8y=6y-2+10
 
$ $|Add \ 10 \ to \ both \ sides|$

$
8y=6y+8
 
$

$
8y-6y=8
 
$ $|Subtract \ 6y \ from \ both \ sides|$

$2y=8$

$y=8/2$ $|Divide \ both \ sides \ by \ 2|$

$y=4$

$\star \ Hence \ solved$

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2 years ago

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After John worked at a job for 10 years, his salary doubled. If he started at $x, hls salary after 10 years is

Sholpan [36]

Answer:

$2x

Step-by-step explanation:

x × 2 = 2x

I hope this helps!

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3 years ago

Indicate the general rule for the arithmetic sequence with a3 = -12 and a8 = -37

Mandarinka [93]

Answer:

The general rule is $a_n = -2 - 5(n-1)$

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference between consecutive terms is always the same, and this difference is called common difference.

The general rule of an arithmetic sequence is given by:

$a_{n} = a_1 + (n-1)d$

In which $a_1$ is the first term and d is the common difference.

We can also find the nth term as a function of a term m, using:

$a_n = a_m + (n-m)d$

a3 = -12 and a8 = -37

First we find the common difference. So

$a_n = a_m + (n-m)d$

$a_8 = a_3 + (8-3)d$

$-37 = -12 + 5d$

$5d = -25$

$d = -\frac{25}{5}$

$d = -5$

So

$a_n = a_1 - 5(n-1)$

Finding the first term:

$a_n = a_1 - 5(n-1)$

Since $a_3 = -12$

$a_n = a_1 - 5(n-1)$

$a_3 = a_1 - 5(3-1)$

$a_1 = a_3 + 10 = -12 + 10 = -2$

So the general rule is:

$a_n = a_1 - 5(n-1)$

$a_n = -2 - 5(n-1)$

6 0

2 years ago

Subtract.<br> (4x + 7) - (x+1)<br> A. 3x + 8<br> B. 3x + 6<br> C. 4x + 8<br> O D. 4x + 6<br><br> Lmk

Studentka2010 [4]

Answer:

4x + 7 - ( x + 1)

Remove the bracket

We get

4x + 7 - x - 1

= 3x + 6

That's option B

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2 years ago

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liq [111]

Answer:

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2 years ago

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