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Rufina [12.5K]
2 years ago
6

7 2/15 + 5 2/3 +9 13/15

Mathematics
1 answer:
crimeas [40]2 years ago
4 0

21+

15

2

+

3

2

+

15

13

LCD = 1515

21+

15

2

+

3×5

2×5

+

15

13

21+

15

2+10+13

21+1

15

10

22

15

10

15

10

3

2

22

3

2

done

the answer of this question is last one

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Softa [21]

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Step-by-step explanation: This problem states that the sum of 4 consecutive numbers is 218 and it asks us to find the numbers.

4 consecutive numbers can be represented as followed.

X ⇒ <em>first number</em>

X + 1 ⇒ <em>second number</em>

X + 2 ⇒ <em>third number</em>

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4x + 6 = 218

      -6     -6   ← <em><u>subtract 6 from both sides of the equation</u></em>

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÷4    ÷4   ← <u><em>divide both sides of the equation by 4</em></u>

 <u>X = 53</u>

<u />

X ⇒ <em>first number   = 53</em>

X + 1 ⇒ <em>second number   = 54</em>

X + 2 ⇒ <em>third number   = 55</em>

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<em />

<em>Therefore, our 4 consecutive numbers are </em><em>53</em><em>, </em><em>54</em><em>, </em><em>55</em><em>, and </em><em>56</em><em>.</em>

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