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Norma-Jean [14]
2 years ago
6

Pls, look at the picture for the question.

Mathematics
2 answers:
avanturin [10]2 years ago
8 0

Answer:

1. 9 * 10^15 meters per years

2. 3*10^8 meters per second

Step-by-step explanation:

Light travels is given 9,... m per year.

They ask how many meter light trravels per years.

They give you the meter per year so you look at the values and move the decimal and see if it can round to the whole number 9.

Looking at the four next to nine can't round so 9,460,000,000,000 becomes 9 * 10^15 m per year.

Converting meters per year to meter per seconds

\frac{9*10^5meters}{1 year} *\frac{1year}{365 days}*\frac{1 day}{24 hrs} *\frac{1hr }{60 min}*\frac{1min}{60 secs}

The answer should be 2.8*10^8 or 3*10^8 meters per second

finlep [7]2 years ago
7 0
B. 9*10^16 (because in question give it)


B. 3*10^9 (because answer to first question is divided by seconds in one year (365*24*60*60).
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18. The table shows the amount of money in a savings account after several weeks
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Answer:

a. Arithmetic

b. a_{n} = a_{n-1} + 15

c. a_{n} = 15n + 125

Step-by-step explanation:

A sequence is arithmetic when the difference between one term and the next is a constant. On the other hand, a sequence is geometric when the next term is found by multiplying the previous by a constant.

In this case, the next term of the sequence can be found by adding $15. Therefore, the sequence is ARITHMETIC ✔️

The recursive formula will be the following: a_{n} = a_{n-1} + 15

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(03.01)<br> Is the following relation a function? (1 point)<br> O Yes<br> O No
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3 years ago
Sleep apnea is a disorder in which there are pauses in breathing during sleep. People with this condition must wake up frequentl
Pachacha [2.7K]

Answer:

a) 0.24356 or 24.36%

b) [102.39 , 105.61]

c) The interpretation of this confidence interval is that in samples of 427 people aged 65 years and older, there is a 99% probability that the number of people that suffers sleep apnea is between 103 and 105.

Step-by-step explanation:

a)

This can be considered a binomial distribution (a person either has sleep apnea or not).

Based on the sample we have the probability of suffering the condition is  

p = 104/427 = 0.24356  

and q (the probability of not suffering the condition) is  

q=1-0.24356=0.75644

So the proportion of people aged 65 years and older who have sleep apnea is 0.24356 or 24.36%

b)

To check if we can <em>approximate this binomial distribution with the Normal distribution</em> we must see that

np ≥ 5 and nq ≥ 5

where n is the sample size. Since

427*0.24356 ≥ 5 and 427*0.75644 ≥ 5  

we can approximate the binomial with a Normal distribution with mean  

np = 427*0.24356 = 104  

and standard deviation  

\large s=\sqrt{npq}=\sqrt{427*0.24356*0.75644}=8.867

The 99% confidence interval (without the continuity correction factor) is given by the interval

\large [\bar x-z^*\frac{s}{\sqrt n}, \bar x+z^*\frac{s}{\sqrt n}]

where

\large \bar x <em>is the sample mean  </em>

<em>s is the sample standard deviation  </em>

<em>n is the sample size </em>

\large z^* <em>is the 0.01 (99%) upper critical value for </em>

<em>the Normal distribution N(0;1). </em>

The value of \large z^* can be found either by using a table or a computer to find it equals to  

\large z^*=2.576

and our 99% confidence interval <em>(without continuity correction) </em>is

\large [104-2.576*\frac{8.867}{\sqrt{427}}, 104+2.576*\frac{8.867}{\sqrt {427}}]=[102.8946,105.1054]

We can now introduce the continuity correction factor. This should be done because <em>we are approximating a discrete distribution (Binomial) with a continuous one (Normal). </em>

This is simply done by widening the interval in 0.5 at each end, so our final 99% confidence interval is

[102.3946 , 105.6054] = [102.39 , 105.61] rounded to 2 decimal places.

c)

The interpretation of this confidence interval is that in samples of 427 people aged 65 years and older, there is a 99% probability that the number of people that suffers sleep apnea is between 103 and 105.

If another study found a 15% of elderly people suffered sleep apnea, that would mean that in a sample of 427 only 64 would have the condition. Since that number is less than 103 by far, that would give us a reason to doubt about the conditions that framed the study (sample size, sampling method, age of people, etc.)

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