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Amiraneli [1.4K]
3 years ago
10

What is an equation for the linear function whose graph contains the points (−1, −2) and (3, 10)

Mathematics
2 answers:
Bas_tet [7]3 years ago
8 0
First you draw a gragh then draw the points and connect them that easy
sladkih [1.3K]3 years ago
4 0
The equation of a line starting from two points is:
y-y_1=\frac{y_2-y_1}{x_2-x_1} \cdot (x-x_1)

From the first point you get: x1 = -1, y1 = -2
From the second point you get: x2 = 3, y2 = 10

Replace x1, y1, x2, y2 in the equation of the line and you get:
y+2=\frac{10+2}{3+1} \cdot (x+1)
y+2=\frac{12}{4} \cdot (x+1)
y+2=3 \cdot (x+1)

From this you get the equation of your line:
y(x)=3x+1




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Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
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Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

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