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xenn [34]
4 years ago
8

What is the radius of a circle whose equation is (x + 5)^2 + (y – 3)^2 = 42?

Mathematics
2 answers:
aliya0001 [1]4 years ago
8 0

Answer:

4 units

Step-by-step explanation:

natita [175]4 years ago
7 0
The equation of a circle centered at point (x1,y1) with a radius r is given by

(x-x_1)^2 + (y-y_1)^2 = r^2

are you sure you wrote down the problem correctly?
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I need help thank you
Alenkasestr [34]
Hello again! 
So just like in the last problem you would do the same here.
Solve for 3y + 6 = 3
Subtract 6 from both sides.
3y = -3
Divide by 3.
y = -1
Now plug it into 8y + 2.
8(-1) + 2 = ?
-8 + 2 = ?
= -6
I hope this helps love! :)
5 0
3 years ago
-7 (5y - 2u - 5)<br> Use the distributive property to remove parentheses
Montano1993 [528]
Times -7 by everything in the parentheses. so

-7 times 5y=-35y
-7 times -2u=14u
-7 times -5 = 35

therefore 35y+14u+35
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=y%20%3D%204%287%29%20%7B7%7D%5E%7Bx%7D%20" id="TexFormula1" title="y = 4(7) {7}^{x} " alt="y =
jeyben [28]

Answer:

Step-by-step explanation:

8 0
3 years ago
12345678910 Using the greatest common factor for the terms, how can you write 80 + 32 as a product?
Romashka-Z-Leto [24]
Find the GCF of 80 and 32.  

I'd start by identifying possible integer factors of both 80 and 32:
80:  {1,2,4,5,8,10,16,20, 40, 80}

32:  {1, 2,4, 8, 16, 32}

Working backwards, we see that the first factor that is represented in both lists is 16.  Is 80 evenly divisible by 16?  Yes; the quotient is 5.
                  Is 32 evenly divisible by 16?  Yes; the quotient is 2.

You could writet 80 + 32 as 16(5 + 2).  This is a product equal to 112, just as 80 + 32 = 112.
5 0
4 years ago
PLEASE HELP WILL MARK BRAINLIEST
Romashka [77]

Answer:

A.The mean would increase.

Step-by-step explanation:

Outliers are numerical values in a data set that are very different from the other values. These values are either too large or too small compared to the others.

Presence of outliers effect the measures of central tendency.

The measures of central tendency are mean, median and mode.

The mean of a data set is a a single numerical value that describes the data set. The median is a numerical values that is the mid-value of the data set. The mode of a data set is the value with the highest frequency.

Effect of outliers on mean, median and mode:

  • Mean: If the outlier is a very large value then the mean of the data increases and if it is a small value then the mean decreases.
  • Median: The presence of outliers in a data set has a very mild effect on the median of the data.
  • Mode: The presence of outliers does not have any effect on the mode.

The mean of the test scores without the outlier is:

   \bar{x}=\frac{Total of the observations-Outlier value}{n-1} \\=\frac{(86*16)-72}{15} \\=\frac{1304}{15}\\ =86.9333

*Here <em>n</em> is the number of observations.

So, with the outlier the mean is 86 and without the outlier the mean is 86.9333.

The mean increased.

Since the median cannot be computed without the actual data, no conclusion can be drawn about the median.

Conclusion:

After removing the outlier value of 72 the mean of the test scores increased from 86 to 86.9333.

Thus, the the truer statement will be that when the outlier is removed the mean of the data set increases.

4 0
3 years ago
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