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3 years ago

What is the radius of a circle whose equation is (x + 5)^2 + (y – 3)^2 = 42?

Mathematics

2 answers:

aliya0001 [1]3 years ago

8 0

Answer:

4 units

Step-by-step explanation:

natita [175]3 years ago

7 0

The equation of a circle centered at point (x1,y1) with a radius r is given by

$(x-x_1)^2 + (y-y_1)^2 = r^2$

are you sure you wrote down the problem correctly?

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Which system is equivalent to y= 9x^2 x+y=5 ?

melomori [17]

Answer : Option A

Explanation:

we can clearly see that from x+ y=5 we can substitute y = 5-x in y = 9x^2

Option B is clearly incorrect x can not be y -5

Option C is incorrect because y can not be 5 +x

Option D is incorrect because its y = 9x^2 not y^2 =9x^2 so y can not be 3x

if its y^2 = 9x^2 then only implies y = 3x

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3 years ago

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The area of a square is 100 m². What is its perimeter?

puteri [66]

Answer:

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2 years ago

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What is 850 in scientific notation?

jonny [76]

Answer:

it is 8.5 x 10^2 because when you times the 10 twice and then multiply it with 8.5 and the decimal moves

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2 years ago

HELP PLEASE ITS JUST ONE QUESTION

Nady [450]

Answer:

y = 2x - 1

Step-by-step explanation:

The given line is y = 2x - 6.

It is in the y = mx + b form, where m is the slope, so its slope is 2.

We need a line that passes through point P(3, 5) and has slope 2.

y = mx + b

Put the slope in m.

y = 2x + b

Use the given point with x = 3 and y = 5 and solve for b.

5 = 2(3) + b

b + 6 = 5

b = -1

The equation is

y = 2x - 1

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2 years ago

the hardcover version of a book weighs 7 ounces while its paperback version weighs 5 ounces. Forty-five copies of the book weigh

Nuetrik [128]

Keywords:

System of equations, variables, hardcover version, paperback version, books

For this case we must construct a system of two equations with two variables. Let "h" be the number of hardcover version books, and let "p" be the number of paperback version books. If the hardcover version of a book weighs 7 ounces and the paperback version weighs 5 ounces, to reach a total of 249 ounces we have:

$7h + 5p = 249$ (1)

On the other hand, if there are Forty-five copies of the book then:

$h + p = 45$ (2)

If from (2) we clear the number of books paperback version we have:

$p = 45-h$

As each paperback version book weighs 5 ounces, to obtain the total weight of the paperback version books, represented by "x" in the table shown, we multiply $5 * p = 5 (45-h)$

So, $x = 5 (45-h)$

Answer:

$x = 5 (45-h)$

Option D

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3 years ago

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