The answer would be 5/2q+9r+6r-20s
Explanation
We have the equation
5(1/2q+3r-4s)
which would equal
5/2q+15r-20s
so with the information
We can subtract 6r from 15r to get 9r
15r-6r=9r
+9r would be the missing piece
So we substitute it in to make the equation true.
5/2q(+9r)+6r-20s
Hope this helps or was correct
Answer:
hello!
Step-by-step explanation:
Answer:
The short answer is there isn’t.
Start by writing each of these as an expression:
x * y = 60
x + y = 7
Next, solve each for the same variable; in this case, y:
(x * y) / x = 60 / x
.: y = 60 / x
(x + y) - x = 7 - x
.: y = 7 - x
Next, replace y of the second expression to the first
y = 60 / x & y = 7 - x
.: 7 - x = 60 / x
Now, solve for x:
(7 - x) * x = (60 / x) * x
.: x * 7 - x^2 = 60
This is quadratic, so write it in the form of ax2 + bx + x = 0
(-1)x^2 + (7)x + (-60) = 0
.: a = -1, b = 7, c = -60
Finally solve for b:
x = (-b +- sqrt(b^2 - 4*a*c)) / 2a
.: x = (-7 +- sqrt(7^2 - 4*-1*-60)) / (2 * -1)
.: x = (-7 +- sqrt(49 - 240)) / -2
.: x = (-7 +- sqrt(-191)) / -2
The square root of a negative value is imaginary and thus there’s no real answer to this problem.
Answer:−
18
Step-by-step explanation:
Answer:
1111111111111111
Step-by-step explanation:
222222222222
