For the lines to be parallel the two angles need to be equal to each other:
128-x = x
Add 1x to both sides
128 = 2x
Divide both sides by 2:
X = 128/2
X = 64
Answer: x = 64
Step-by-step explanation:
I think you did not copy the correct information of your answer options here.
because, as you wrote the 4 options, none of them are correct.
remember, the area of a triangle is base times height divided by 2
A = (b × h) / 2
given the numbers in the problem statement
b = 5, h = 8
A = (5 × 8) / 2 = 40 / 2 = 20
you need to pick the answer option in your original document that would lead to 20.
none of the 4 options you gave me here would result in 20. so, there must be something wrong with them.
Answer:


Step-by-step explanation:
First, identify the slope.
We are given the line y=7x-5.
This is in slope intercept form or y=mx+b where m is the slope and b is the y-intercept. So, the coefficient to x, or 7 in this case, is the slope.
Now, find the parallel and perpendicular slopes.
1. Parallel Slope
Parallel lines never intersect, so they have the same slope. A parallel line has a slope of 7.
2. Perpendicular Slope
Perpendicular slopes intersect to form right angles. They have negative reciprocal slopes.
- Negate the slope: 7⇒ -7
- Find the Reciprocal (flip the numerator and denominator: -7/1 ⇒ -1/7
A parallel line has a slope of 7 and a perpendicular line has a slope of -1/7.
Answer: y= -x + 7
Solution:
Step 1 : find the slope using the equation using the pair of coordinates that are given i.e A (−7,14) B (−21,28) ( name them A and B respectively so they can be easily named as x1, y1 and x2,y2 respectively)
m = y2-y1/x2-x1
m = 28-14 / -21 -( -7)
m = 14 / -14
m = -1
Step 2 : Find the y intercept using the line of equation (use and one of the given coordinates either A or B)
Using A ( -7, 14)
y= mx+ b
14 = (-1)(-7) + b
14= 7 + b
14-7 = b
7 =b
So,
y=mx+b
Insert m and b
y= -x + 7
7 units bc I took the test already