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hjlf
2 years ago
6

Line segment XY begins at (-6,4) and ends at (-2,4). The segment is reflected over the x-axis and translated left 3 units to for

m line segment X'Y'.
Enter the length, in units, of line segment X'Y'.
Mathematics
1 answer:
Marat540 [252]2 years ago
5 0

Line segment XY begins at (-6,4) and ends at (-2,4); XY is reflected over the x-axis and translated left 3 units to form line segment X'Y' which has a length of 4 units.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Line segment XY begins at (-6,4) and ends at (-2,4). Hence:

XY = \sqrt{(4-4)^2 + (-2 +6)^2} \\\\XY = \sqrt{0+16} \\\\XY = \sqrt{16} \\\\XY = 4

XY is reflected over the x-axis and translated left 3 units to form line segment X'Y'. Hence:

XY = X'Y' = 4 units

Line segment XY begins at (-6,4) and ends at (-2,4); XY is reflected over the x-axis and translated left 3 units to form line segment X'Y' which has a length of 4 units.

Find out more on equation at:

brainly.com/question/2972832

#SPJ1

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