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Sergeu [11.5K]
1 year ago
9

Theorem: A line parallel to one side of a triangle divides the other two

Mathematics
1 answer:
Nonamiya [84]1 year ago
7 0

Answer: Segment BD = 15

Step-by-step explanation: Ok. So, we know that segment DE is parallel to segment BC and segment EF is parallel to segment AB. The triangle proportionality theorem states that if a line is parallel to one side of a triangle and also intersects the other two sides, the line divides the sides proportionally. To put it more simply; because segment EF is parallel to segment AB, triangles ADE and EFC are proportional and similar. From there we must find the scale factor by which these two triangles are proportional.

We can do this by dividing the corresponding segments by; each other.

24 ÷ 20 = 1.2

Scale Factor = 1.2

Then we divide segment AD (18) by the scale factor (1.2).

18 ÷ 1.2 = 15

Since segment EF is parallel to segment AB, segment EF corresponds and is congruent to segment DB.

So,

Segment BD = 15

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If 20% of a number p is 10, what is 10% of p?
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Answer:

5

Step-by-step explanation:

20% of p = 10

20% = 0.2

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Multiply both sides of the equation by 5

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Find 10% of p

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5

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Hope this helps :)

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use symbols to compare the numbers 512 and 521. write the comparison to ways. then explain your thinking
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Solution:-  Given numbers to compare are 512 and 521 .

As they are 3 digit numbers

So, we have to compare hundreds place.

But hundreds are equal in both the numbers with digit 5.

Next we have to compare tens place.

Case 1 :- 1 ten is smaller in 512 than 2 tens in 521 .

So we get the result that,

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Case 2:-2 tens is greater in 521 than 1 ten in 512 .

So we get the result that,

521 is greater than 512

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