3 years ago

Find three consecutive even integers whise sum is 222

2 answers:

8 0

72+74+76=222 hope you understand it

6 0

74....74....74............

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Molodets [167]

Part 1

$f(a)=4-7a+16a^2$

Part 2

$f(a+h)=4-7(a+h)+16(a+h)^2\\\\=4-7(a+h)+16(a^2 +2ah+h^2)\\\\=4-7a-7h+16a^2 +32ah+16h^2$

Part 3

$\frac{f(a+h)-f(a)}{h}=\frac{(4-7a-7h+16a^2 +32ah+16h^2-(4-7a+16a^2)}{h}\\\\=\frac{-7h+32ah+16h^2}{h}\\\\=32a+16h-7$

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1 year ago

CaHeK987 [17]

Your answer is c. As you multiply 1/2 by both of the factors inside the parentheses you’ll find that 1/2(b-30)=1/2b-15

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3 years ago

zzz [600]

The answer is 48 i think

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3 years ago

Svet_ta [14]

Answer:

the answer is 5.1 killograms

Step-by-step explanation:

hope this helps

8 0

2 years ago

jasenka [17]

Answer:

multiply by 2

Step-by-step explanation:

G, H, K -> your multiply by 2 to get G',H',and K'

3 0

3 years ago