4(x - 4) + 65 = -3x
4(x) - 4(4) + 65 = -3x
4x - 16 + 65 = -3x
4x + 49 = -3x
- 4x - 4x
49 = -7x
-7 -7
-7 = x
Answer:
$230
Step-by-step explanation:
100%-20%=80%
80%=184
1%=184÷80=2.3
100%=2.3x100=$230
Hope this helps! Thanks.
Answer:
i think its photosinthisis because...
Step-by-step explanation:
Sometime around 3 billion years ago (about 1.5 billion years after Earth formed!), photosynthesis began. Photosynthesis allowed organisms to use sunlight and inorganic molecules, such as carbon dioxide and water, to create chemical energy that they could use for food.
Hope this helps and maybe a brainlest?
Answer:
If m is nonnegative (ie not allowed to be negative), then the answer is m^3
If m is allowed to be negative, then the answer is either |m^3| or |m|^3
==============================
Explanation:
There are two ways to get this answer. The quickest is to simply divide the exponent 6 by 2 to get 6/2 = 3. This value of 3 is the final exponent over the base m. Why do we divide by 2? Because the square root is the same as having an exponent of 1/2 = 0.5, so
sqrt(m^6) = (m^6)^(1/2) = m^(6*1/2) = m^(6/2) = m^3
This assumes that m is nonnegative.
---------------------------
A slightly longer method is to break up the square root into factors of m^2 each and then apply the rule that sqrt(x^2) = x, where x is nonnegative
sqrt(m^6) = sqrt(m^2*m^2*m^2)
sqrt(m^6) = sqrt(m^2)*sqrt(m^2)*sqrt(m^2)
sqrt(m^6) = m*m*m
sqrt(m^6) = m^3
where m is nonnegative
------------------------------
If we allow m to be negative, then the final result would be either |m^3| or |m|^3.
The reason for the absolute value is to ensure that the expression m^3 is nonnegative. Keep in mind that m^6 is always nonnegative, so sqrt(m^6) is also always nonnegative. In order for sqrt(m^6) = m^3 to be true, the right side must be nonnegative.
Example: Let's say m = -2
m^6 = (-2)^6 = 64
sqrt(m^6) = sqrt(64) = 8
m^3 = (-2)^3 = -8
Without the absolute value, sqrt(m^6) = m^3 is false when m = -2
Answer:
pift^2(or your third option) is the area of a circle with a radius of 1.