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shtirl [24]
1 year ago
10

An equation in the form ax2+bx+c=0 is solved by the quadratic formula. The solution to the equation is shown below.x=−7±√ "572"

What are the values of a, b, and c in the quadratic equation?
A: a= 1, b= -7, c = -2
B: a = 1, b= 7, c = -2
C: a = 2, b = -7, c = -1
D: a = 2, b = 7, c = -1
Mathematics
2 answers:
GarryVolchara [31]1 year ago
6 0

Let's see

  • x=-b±√b²-4ac/2a

On comparing

  • -b=-7
  • b=7

And

  • 2a=2
  • a=2/2
  • a=1

So

  • b²-4ac=57
  • 7²-4c=57
  • 4c=49-57
  • 4c=-8
  • c=-2

Option B

7nadin3 [17]1 year ago
4 0

Answer:

B: a = 1, b= 7, c = -2

Explanation:

\sf Quadratic \ Equation : \dfrac{-b\pm \sqrt{b^2 - 4ac} }{2a}

Knowing This:

<u>solve for b</u>

  • -b = -7
  • b = 7

<u>solve for a</u>:

  • 2a = 2
  • a = 1

<u>solve c</u>:

  • b² - 4ac = 57
  • 7² - 4(1)(c) = 57
  • -4c = 57 - 49
  • -4c = 8
  • c = 8/-4 = -2
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Answer:

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5 0
2 years ago
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PLEASE HELP ASAP
Shtirlitz [24]

Answer:

i think its photosinthisis because...

Step-by-step explanation:

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2 years ago
What is the square root of m^6?
Nastasia [14]
Answer:
If m is nonnegative (ie not allowed to be negative), then the answer is m^3
If m is allowed to be negative, then the answer is either |m^3| or |m|^3

==============================

Explanation:

There are two ways to get this answer. The quickest is to simply divide the exponent 6 by 2 to get 6/2 = 3. This value of 3 is the final exponent over the base m. Why do we divide by 2? Because the square root is the same as having an exponent of 1/2 = 0.5, so
sqrt(m^6) = (m^6)^(1/2) = m^(6*1/2) = m^(6/2) = m^3
This assumes that m is nonnegative. 

---------------------------

A slightly longer method is to break up the square root into factors of m^2 each and then apply the rule that sqrt(x^2) = x, where x is nonnegative

sqrt(m^6) = sqrt(m^2*m^2*m^2)
sqrt(m^6) = sqrt(m^2)*sqrt(m^2)*sqrt(m^2)
sqrt(m^6) = m*m*m
sqrt(m^6) = m^3
where m is nonnegative

------------------------------

If we allow m to be negative, then the final result would be either |m^3| or |m|^3. 

The reason for the absolute value is to ensure that the expression m^3 is nonnegative. Keep in mind that m^6 is always nonnegative, so sqrt(m^6) is also always nonnegative. In order for sqrt(m^6) = m^3 to be true, the right side must be nonnegative.

Example: Let's say m = -2
m^6 = (-2)^6 = 64
sqrt(m^6) = sqrt(64) = 8
m^3 = (-2)^3 = -8
Without the absolute value, sqrt(m^6) = m^3 is false when m = -2

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Answer:

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