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3 years ago

Need some help please!!

Mathematics

1 answer:

ella [17]3 years ago

6 0

Answer:

The other point on the diameter which is also on the circle is; (-3, 2)

Step-by-step explanation:

The center of the circle, also a point where the diameter crosses, is (3, 6)

The diameter touches the circle at point (9, 10)

The displacement is (9 - 3, 10 - 6) = (6, 4)

This means that we move, +6 units along the x-axis and +4 units along the y-axis , from the center of the circle in order to reach point (9, 10)

If we want to reach the other point on the diameter which also on the circle, we move -6 units along the x-axis and -4 units along the y-axis to get;

(3, 6) - (6, 4) = (-3, 2)

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Can someone tell me why the answer is 2?

Ira Lisetskai [31]

Answer:

If we put x=2 in the given equation, we get the answer for the equation as 2

Given:

$\sqrt{-3 x+10}=x$

To find:

Why the answer is 2

Solution:

If we substitute the value x=2 in the given option, we get

$\sqrt{-3(2)+10}=2$

$\sqrt{-6+10}=2$

$\sqrt{4}=2$

Result:

Thus we can say that when substitute the value of x=2

We get the answer as $\sqrt{-3 x+10}=2$

8 0

3 years ago

A trucker handed in a ticket at a toll booth showing that in 2 hours she had covered 159 on a toll road with a posted speed limi

Nimfa-mama [501]

Answer:

overspeeding,

see if we calculate the speed or average speed,

it would be 159/2 which would be 79.5mph,

so as posted speed was 65mph, but the average speed was 79.5mph(Meaning most of the time she would have been above 65 mph), So,

She would have been charged with overspeeding

HOPE IT HELPS

BYE!

4 0

2 years ago

What is .36 repeating expressed as the quotient of two integers in simplest form?

Igoryamba

$x=0.\overline{36}\\
100x=36.\overline{36}\\
100x-x=36.\overline{36}-0.\overline{36}\\
99x=36\\
x=\dfrac{36}{99}\\
x=\dfrac{4}{11}$

5 0

3 years ago

Use the definition of the derviative to compute the derivative of f(x)= 1- 7x^2 at the specific point x=2.

GaryK [48]

Answer:

$f'(x) = -28 \ at \ x = 2$

Step-by-step explanation:

$f'(2) = \lim_{h \to 0}\frac{f(2+h)) -f(2)}{h} \\\\f(2+h) = 1 - 7(2+h)^2 = 1 - 7(4 +h^2 +4h) = 1 - 28 - 7h^2 - 28h = - 7h^2 -28h - 27\\\\f(2) = 1 - 7(2^2) = 1 - 28 = -27\\\\f(2+h) - f(2) = -7h^2 - 28h - 27 - (-27) = -7h^2 -28h -27 + 27 = -7h^2 -28h\\\\f'(2) = \lim_{h \to 0}\frac{-7h^2 - 28h}{h} \\\\$

$= \lim_{h \to 0} \frac{h(-7h -28)}{h}\\\\= \lim_{h \to 0} (-7h -28)}\\\\= -7 (0) - 28\\\\= -28$

4 0

2 years ago

The function f(x)=(2/5)x is shown on the coordinate plane.

kow [346]

None of these answer choices are correct. As X decreases f of x decreases without bound as X increases f of x increases without bound look to be sure you copied the question right

5 0

3 years ago

Need some help please!!​

Need some help please!!