The expression is a product expression
The denominator of the simplified fraction is 3n -2
<h3>How to determine the denominator?</h3>The expression is given as;
Divide the first fraction by 2/2
Evaluate the above product
The above fraction is a simplified fraction of , and the denominator is 3n - 2
Hence, the denominator of the simplified fraction is 3n -2
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The question requires one to indicate the correct terms for the reactant from left to right.
<h3>What is a reactant?</h3>A reactant is a material that enters and changes during a chemical reaction.
1. Reactant A (Gains/Loses) and electron to become product B
To produce B, reactant A loses one electron. The loss of one electron from an atom causes the atom to be oxidized.
Reactant A gives an electron to NAD+ and is transformed to B+ in the given reaction there is an increase in the positive charge. As a result, reactant A is oxidized to produce B+.
2. NAD+ becomes reduced in the process of the reaction.
NAD+ receives the electron given to it by reactant A and is reduced to NADH. As a result, the positive charge of NAD+ decreases.
3. NADH is more reduced than NAD+
NAD+ receives an electron and becomes NADH. As a result, NADH is decreased more than NAD+
4. NAD+ is in the more oxidized state compared to NADH
NAD+ has a surplus of positive charge as opposed to NADH. NAD+ must receive one electron in order to produce NADH. As a result, as opposed to NADH, NAD+ is more oxidized.
5. Reactant A is the electron donor in this reaction.
Reactant A loses one electron, resulting in positively charged B+. This electron is taken up by NAD+, which reduces to NADH. As a result, the electron donor is reactant A.
6. Reactant A is the reducing agent in this reaction.
A reducing agent is a molecule that can transfer electrons.
Such a molecule has the potential to decrease another molecule while also becoming oxidized. Reactant A is the reducing agent in the given reaction, donating an electron to NAD+.
Following the electron transfer, reactant A is oxidized to product B+, and NAD+ is reduced to NADH.
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