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kaheart [24]
2 years ago
8

For the function f (x)=√x+3, the average rate of change to the nearest hundredth over the interval 2≤x≤8 is

Mathematics
1 answer:
Reptile [31]2 years ago
3 0

Answer:

0.24 to nearest hundredth.

Step-by-step explanation:

f (x)=√x+3

f(2) = √2 + 3

f(8) = √8 + 3

Average rate of change = (√8 + 3 - (√2 + 3)) / (8-2)

= (2√2 - √2)/6

= √2/6

= 0.2357

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