It take 23 mins for the drive
He needs to reach the airport by a quarter before 6
a quarter before 6 = 5.45
So he needs to leave 23 mins before 5.45
23 mins before 5.45 = 5.22
1,35 3,57
slope = (57 - 35)/(3 - 1) = 11
y = 11 x + b
35 = 11 (1) + b
b= 24
y = 11x + 24
y = 11(5) + 24 = 79
It is B. You divide 10 by 25 and multiply it by 100
Answer:
the buses are at 50 mph and 60 mph
the distance = 210 miles
Step-by-step explanation:
r1 = rate of bus 1
r2 = rate of bus 2
r1 = r2+10 (The speed of one of the buses was 10 mph greater than the speed of the other bus.)
distance = rate * time
for bus 1
distance = r1 * (3.5)
bus 2 was 1/6 short of making it to town b
so it made it 5/6 of the way
5/6 distance = r2 * (3.5)
multiply by 6/5 on each side
distance = 6/5 * r2 * 3.5
set the distances equal
r1 * (3.5)=6/5 * r2 * 3.5
r1 = 6/5 * r2
now set rate 1 equal (r1 = r2+10)
6/5 * r2 = r2 + 10
solve for r2 by subtracting r2 on each side
6/5 r2 -r2 = 10
6/5 = 1.2
1.2 r2 - r2 =10
.2 r2 = 10
divide by .2 on each side
r2 = 10/.2
r2 = 50
r1 = 50 + 10
r1 =60
to find the distance
distance = r1 * (3.5)
distance = 60 * 3.5
distance = 210 miles
