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Marina86 [1]
2 years ago
6

Please help! Will give brainliest!A bowl has 3 red beads and 7 blue beads. Two beads are selected at random one at a time. First

a red bead i
drawn and placed on a table. Next a blue bead iS drawn.
What IS the probability of this event?
Drag and drop the answers into the boxes to complete the sentences.

Mathematics
1 answer:
densk [106]2 years ago
8 0

Answer:

7/30

Step-by-step explanation:

10 beads    3 red      1st red prob = 3/10    

   now there is 9 beads    7 blues    2nd blue prob = 7/9

3/10 * 7/9 = 21/90  = 7/30

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16+90+2y =180 since it is a straight line

106 +2y = 180

subtract 106 from each side

2y = 74

divide by 2 on each side

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90+2y+O = 180 since it is a straight line

90 + 2(37) +O = 180

90+74 +O = 180

164+0 =180

subtract 164 from each side

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O +4x+90=180 sine it is a straight line

16 + 4x +90 = 180

106 +4x = 180

subtract 106 from each side

4x = 74

divide by 4

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