All categories

3 years ago

Please could someone help!

Mathematics

1 answer:

melisa1 [442]3 years ago

8 0

Answer:

<h2> $32.16 \: grams$ </h2>

solution,

$mass = volume \times density \\ \: \: \: \: \: \: \: \: = 2.4 \: \frac{g}{ {cm}^{3} } \times 13.4 \: {cm}^{3} \\ \: \: \: \: \: \: \: \: = 2.4 \times 13.4 \: \: grams \\ \: \: \: \: \: \: \: \: \: \: = 32.16 \: \: grams$

Hope this helps...

Good luck on your assignment..

You might be interested in

Tiffany is filling her daughters pool with water from a hose. She can fill the pool at a rate of 1/10 gallons/second. Create at

ololo11 [35]

Three equivalent ratios that are associated with this rate would be 6 gallons/1min, 360gallons/1 hour and 720 gallons/2hours.
I'm sorry but I can't explain or show how to use a double number line for this question.

7 0

3 years ago

Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.

Arada [10]

Answer:

a) $0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799$

$0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847$

The 95% confidence interval would be given by (0.799;0.847)

b) $n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79$

And rounded up we have that n=622

c) $n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

Step-by-step explanation:

Part a

$\hat p=\frac{823}{1000}=0.823$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

If we replace the values obtained we got:

$0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799$

$0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847$

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.03$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79$

And rounded up we have that n=622

Part c

$n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

5 0

3 years ago

What is the volume of the cone below?

nataly862011 [7]

Answer:

96 pi

Step-by-step explanation:

The formula for the volume of a cone is V=pi*r^2*h/3 the radius is 4 and the height is 18 plug in those values into the equation to get V=pi*16*6 16*=96 so the answer is 96 pi.

3 0

3 years ago

Read 2 more answers

If an adult male’s height is h inches over five feet, his approximate normal weight is given by the expression 6.2(20 + h). What

Harlamova29_29 [7]

If this male is 5 ft 9 inches tall, he is 9 inches over five feet tall. Thus, h = 9.
Evaluate 6.2(20+h):

6.2(20+9) = 6.2(29) = 179.8 lb.

3 0

4 years ago

Driving from Chester to Boxerville, you see a sign that says you have seven miles to go. If the total length of the trip is 45 m

krek1111 [17]

45 - 7 = 38
unknown quantity is the miles already traveled.

6 0

4 years ago

Read 2 more answers