The period is equal to 2pi/n, where n is the coefficient of t. In this case pi/2. Therefore the period in this example is 4. Frequency is equal to 1/period. Hence the frequency for this problem is 1/4
![\sqrt[8]{48^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B8%5D%7B48%5E4%7D%20)
can be rewritten as

to the

power:

Now, applying exponent rules (multiply exponent inside parentheses by the one outside parentheses), we get:

This is equivalent to

, so now, we just simplify:

So:
If Stuart starts with -$54.19 then gains $70.82, you have to add the gained amount to the origin amount. Since the origin amount is negative, you can also subtract the origin amount from the gained amount to find the amount left at the end of the month.
Add 70.82 to -54.19
-54.19 + 70.82 = 16.63
<u>Alternative method:</u>
First, subtract 54.19 from 70.82.
70.82 - 54.19 = 16.63
Add 54.19 to -54.19, bringing you to 0.
-54.19 + 54.19 = 0
Now add the remaining 16.63.
0 + 16.63 = 16.63
<h2>Answer:</h2>
<u>Stuart will have </u><u>$16.63</u><u> at the end of this month.</u>
Answer:
B) 8 and 24.
Step-by-step explanation:
Just by looking at the answer choices, since one number must be three times the other, we can determine that the correct answer is B.
Regardless, let's work this out mathematically. Let the first number be <em>a</em> and the second number be <em>b</em>.
Their difference is 16. Hence:

The first number is three times the second number. So:

Substitute:

Solve for <em>b</em>. Subtract:

And divide both sides by two:

So, the second number is 8.
And since the first number is three times the second, the first number is 24.
Our answer is B as expected.