Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
Answer:
1/2.
Step-by-step explanation:
Probability totals must add up to 1.
P = probability.
If P(any number other than 6) = x, then P(6) = 3x, so
3x + 5x = 1
x = 1/8
P(6) = 3/8 and P(not 6) = 1/8
Therefore P(6 or 1) = 3/8 + 1/8 = 1/2 (answer).
Answer: 28
Step-by-step explanation:
Answer:
94 boxes of samoas
131 boxes of thin mints
Step-by-step explanation:
m=mints
s=samoas
s+m=225 m=225-s
s(2.5)+m(3)=628
2.5s+3m=628
substitute for m
2.5s+3(225-s)=628
2.5s+675-3s=628
reduce
-0.5s=-47
s=94
m=131
