Check the problem again!Cosecant (csc) is the reciprocal of sine (sin) so they are always either both positive or both negative. Perhaps it should be sine < 0 and cosine > 0? In that case, sine is less than zero in quadrants 3 and 4, and cosine is greater than zero in quadrants 1 and 4, so this angle can only lie in quadrant 4. On the unit circle, remember that cosine is the x-coordinate of the terminal side of the angle and sine is the y-coordinate. Quadrant 1 is that where both sine and cosine are greater than zero. The rest of them are numbered consecutively going counter-clockwise; so quadrant 2 has cos < 0 and sin > 0, quadrant 3 has cos < 0 and sin < 0, and quadrant 4 has cos > 0 and sin < 0
9514 1404 393
Answer:
16.9
Step-by-step explanation:
The marked sides are the hypotenuse and the one opposite the angle. The relevant trig function is ...
Sin = Opposite/Hypotenuse
Multiplying by the hypotenuse gives an equation for the opposite side.
x = 22·sin(50°)
x ≈ 16.9
Answer:
Correct option: C -> 2
Step-by-step explanation:
The first equation is:
And the second equation is:
From the second equation, we have:
Using this value of y in the first equation, we have:
Calculating the discriminant Delta, we have:
We have 
, so we have two real values for x, therefore we have two solutions for this system.
Correct option: C.
(If the system of equation is actually:
We would have:
We also have , so we have two solutions for this system.
Correct option: C.)
Answer:
Square the binomial :)
Step-by-step explanation:
Answer:
a = 4
Step-by-step explanation:
a+8 = 12
a= 12-8
a=4
