1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rzqust [24]
2 years ago
14

8 = 1/3 (a+5) Please Help

Mathematics
1 answer:
romanna [79]2 years ago
7 0

Answer:

a = 19

Step-by-step explanation:

a+5/3 (Note: this means a+5 over 3, as in a fraction.)

3 x 8 = a + 5

24 = a + 5

24 + (-5) = (a + 5) + (-5)

19 = (a + 5) - 5

19 = a + 5 - 5

19 = a

a = 19

Hope this helped!

You might be interested in
QUESTION :-
Galina-37 [17]

Answer:

  • 92000

Step-by-step explanation:

<u>Given:</u>

  • I = 5% = 0.05
  • t = 2 years
  • Let the sum is x.

<u>Simple interest:</u>

  • SI = x*2*0.05 = 0.1x

<u>Compound interest:</u>

  • CI = x*(1 + 0.05)² - x = 1.1025x - x = 0.1025x

<u>The difference is 230:</u>

  • 0.1025x - 0.1x = 230
  • 0.0025x = 230
  • x = 230/0.0025
  • x = 92000
3 0
2 years ago
Enter an equation in point-slope form for the line.<br> Slope is 9 and (−3, −1) is on the line.
Korolek [52]

Answer:

y+1=9(x+3)

Step-by-step explanation:

Since the equation for point slope form is y-y₁=m(x-x₁)

enter the given points (-3,-1)

y-(-1)=9(x-(-3))

y+1=9(x+3)           <-- point slope form

8 0
2 years ago
Three lines of crops in a garden form a triangular shape. Strawberries are planted in a 10 ft line and green beans are planted i
Marat540 [252]

Answer:

p = 19.18

Step-by-step explanation:

This question is illustrated using the attachment and will be solved using cosine formula

a^2 = b^2 + c^2 - 2bcCosA

<em>Let the strawberry side be s, the Green beans be b and the pumpkins be p.</em>

<em />

The cosine formula in this case is:

g^2 = s^2 + p^2 - 2spCosG

Where

s = 10

g = 18

The equation becomes

18^2 = 10^2 + p^2 - 2 * 10 * p * Cos\ 68

324 = 100 + p^2 - 20 * p * 0.375

324 = 100 + p^2 - 7.5p

Collect Like Terms

p^2 - 7.5p + 100 - 324 = 0

p^2 - 7.5p - 224 = 0

Using quadratic formula:

p = \frac{-b\±\sqrt{b^2-4ac}}{2a}

Where

a = 1

b = -7.5

c = -224

p = \frac{-(-7.5)\±\sqrt{(-7.5)^2-4*1*-224}}{2*1}

p = \frac{7.5\±\sqrt{56.25+896}}{2}

p = \frac{7.5\±\sqrt{952.25}}{2}

p = \frac{7.5\± 30.86}{2}

p = \frac{7.5 + 30.86}{2} or p = \frac{7.5 - 30.86}{2}

p = \frac{38.36}{2} or p = \frac{-23.36}{2}

p = 19.18 or p = -11.68

But length can not be negative.

So:

p = 19.18

6 0
2 years ago
Help me with these questions plz
UkoKoshka [18]
First, this shoudnt be in mathematics and second, i think this is socila studies.
4 0
2 years ago
Kiran read for x minutes, and Andre read for 5/8 more than that. Write an equation that relates the number of minutes Kiran read
Liula [17]

Answer:  y = 1.625 x

Step-by-step explanation:

Here x represents the time taken by Kiran in reading (in minutes) and y represents the time taken by Andrew in reading (in minutes).

According to the question,

Andre read for 5/8 more than kiran.

Thus, The time taken by Andrew(in minutes) = time taken by kiran + 5/8 of time taken by kiran

= x + \frac{5}{8}\times x

=  \frac{8}{8} + \frac{5}{8}

= \frac{13x}{8}

= 1.625 x

Thus, required equation,

y = 1.625 x

7 0
3 years ago
Read 2 more answers
Other questions:
  • Solve each equation -3(n+5)=27
    13·2 answers
  • Please help quickly,<br>Thank you!<br><br>v v v v v v v v v v v v
    7·2 answers
  • A farmer is enclosing a rectangular area for a pigpen. He wants the length of the pen to be 15 Ft longer then the width. The far
    11·1 answer
  • PLEASE ANSWER + BRAINLIEST!!!!
    10·1 answer
  • Heklp me again please if you dont mind
    15·1 answer
  • Please help
    6·1 answer
  • I NEED HELP ASAPPP!!!<br><br><br> PLEASE HELP MEEE
    11·2 answers
  • Say you want to know if boys are more likely than girls to "wait for their missionary". You take a random sample of 57 males and
    15·1 answer
  • Help me solve please.​
    5·1 answer
  • (inches)
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!