Question

Using his telescope, Tory watches a cheetah as it sits on the top of a cliff. The telescope is positioned so that the line of sight to the cheetah forms a 34° angle of elevation. The telescope sits 2.9 m above the ground and the base of the telescope is 178 m from the base of the cliff. To the nearest tenth of a meter, how high above the ground is the cheetah? If the answer does not have a tenths place then include a zero so that it does. Do not include the units in the answer.

Answer 1

To the nearest tenth of a meter, the height above of the cheetah to the ground is 123.0 meters.

What is a right angle triangle?

A right angle triangle has one of its angles as 90 degrees. The sides can be found using pythagoras theorem or trigonometric ratios.

The distance of the telescope from the base of the cliff is 178 meters and it is the adjacent side of the triangle formed.

Therefore,

tan 34° = opposite / adjacent

tan 34° = opposite / 178

cross multiply

opposite side = 178 tan 34

opposite side = 120.062515998

Therefore,  the height above the cheetah to the ground is as follows:

height =  120.062515998 + 2.9 = 122.962515998

height = 123.0 meters.

learn more on right triangle here:  brainly.com/question/1478228

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