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Korvikt [17]
2 years ago
8

Complete the equilibrium reactions which are pertinent to an aqueous solution of ag2co3. physical states are optional.

SAT
1 answer:
nevsk [136]2 years ago
6 0

The equilibrium reactions pertinent to an aqueous solution of Ag2CO3 in which physical states are not considered is:

\mathbf{Ag_2CO_{3 \ (s)} \rightleftharpoons 2Ag^{+}_{(aq)} + CO_3^{2-}}

<h3>What are equilibrium reactions?</h3>

An equilibrium reaction is a chemical reaction process in which the reactants remain in a steady and stable condition both previously(reactant) and after the reaction is completed(product).

A reaction is considered to be at thermodynamic equilibrium when a reaction meets all three categories of equilibrium;

  • Equilibrium of temperature
  • Equilibrium in the chemical reaction.
  • Equilibrium with the surrounding factors like pressure.

The equilibrium reactions pertinent to an aqueous solution of Ag2CO3 is:

\mathbf{Ag_2CO_{3 \ (s)} \rightleftharpoons 2Ag^{+}_{(aq)} + CO_3^{2-}}

Learn more about equilibrium reactions here:

brainly.com/question/1619133

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A typical neutron star has a mass of about 1. 5msun and a radius of 10 kilometers
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How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.

<h3>Density of the Neutron star</h3>

Density

ρ = m / V

Where:

ρ= density

m = mass of the planet 5.98 10²⁴ km

V =volume of the spherical layer

Volume of a sphere

Volume = 4/3 π r³

Mass = 1.5 = 1.5 1,991 10³⁰

Mass= 2.99 10³⁰ kg

Density:

ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]

ρ is = 7.13 10 17 kg / m³

V = 5.98 10²⁴ / 7.13 10¹⁷

V = 8,387 10⁶ m³

Thickness of the layer

V = 4π r² e

e = V / 4π r

e = 8,387 10⁶ / [4π (10 10³)²]

e = 6.67 10⁻³ m

Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.

Learn more about Density of the Neutron star here:brainly.com/question/15700804

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It get released into the atmosphere

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