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sleet_krkn [62]
2 years ago
7

A mouse runs along a baseboard in your house. The mouse's position as a function of time is given by x(t)=pt2+qt, with p = 0. 40

m/s2 and q = -1. 10 m/s.
SAT
1 answer:
Gelneren [198K]2 years ago
7 0

The  average speed between t = 1.0 s and t = 4.0 s will be 2.1+0.3 which is 2.4m/s

<h3>Velocity function </h3>

Given the equation for the position of the mouse expressed as:

x(t)=pt^2+qt\\

The velocity of the particle is expressed as:

v(t)=2pt+q

Given that p = 0. 40 m/s and q = -1. 10 m/s, the equation will become:

v(t)=2(0.4)t-1.10\\v(t)=0.8t - 1.10

If the time is <em>t = 1.0 s, the velocity will be:</em>

v(1) = 0.8 - 1.10\\v(1) = -0.3m/s

Similarly if t = 4.0ssec, hence:

v(4) = 3.2 - 1.10\\v(4) = 2.1m/s

The  average speed between t = 1.0 s and t = 4.0 s will be 2.1+0.3 which is 2.4m/s

<em>Learn more on</em><em> average speed </em><em>here: brainly.com/question/4931057</em>

Complete question

<em>A mouse runs along a baseboard in your house. The mouse's position as a function of time is given by x(t)=pt 2+qt, with p = 0.40 m/s2and q = -1.10 m/s . Determine the mouse's average speed between t = 1.0 s and t = 4.0 s. I have tried everything and the answer is not 0.40 m/s</em>

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