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alex41 [277]
2 years ago
13

Write the Inequality shown in the diagram below

Mathematics
1 answer:
yuradex [85]2 years ago
8 0

Answer:

-1 ≤ x < 3

Hope this helps ;)

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Evaluate the function rule below when x= -2<br><br> F(x)=3x+2
garri49 [273]
<h2>Answer:</h2><h2>-4</h2><h2 /><h2>Step-by-step explanation:</h2><h2>3 · -2 = -6</h2><h2 /><h2>-6 + 2</h2><h2 /><h2 /><h2>= -4</h2>

<h2><u>Final Anwer = -4</u></h2><h2><u /></h2><h2 /><h2>Hope this helps!! ♥︎</h2>

4 0
3 years ago
Will make the brainly-est due today and all the questions thank you:)​
Lyrx [107]

Answer:

Comic  Books

a: y=-10x+90

b: He will have 10 books at the end of the seventh day.

Step-by-step explanation:

A: Take two points. The y-intercept is (0,90). The graph decreases by 10 each day.

B: Look at day 8.

8 0
4 years ago
Factor of this trinomial x^2 - 11x + 24
dimulka [17.4K]
<span>x^2 - 11x + 24 = (x - 8)(x - 3)

hope it helps</span>
6 0
3 years ago
Find the limit of the function algebraically. limit as x approaches negative three of quantity x squared minus nine divided by q
iris [78.8K]
The limand is continuous at x=-3, so you can directly substitute x=-3 to get

\displaystyle\lim_{x\to-3}\frac{x^2-9}{x^3+3}=\frac{(-3)^2-9}{(-3)^3+3}=\dfrac{9-9}{-27+3}=0

Did you mean to write x^3+3^3=x^3+27 in the denominator by any chance? In that case, you would instead have

\displaystyle\lim_{x\to-3}\frac{x^2-9}{x^3+3}=\lim_{x\to-3}\frac{(x+3)(x-3)}{(x+3)(x^2-3x+9)}=\lim_{x\to-3}\frac{x-3}{x^2-3x+9}=\frac{-3-3}{(-3)^2-3(-3)+9}=-\frac29
5 0
4 years ago
Please I truly need help on this
patriot [66]

Answer:

6

5

Step-by-step explanation:

A polynomial function has as many roots as the degree pf the polynomial.

Question 1:

The degree of the polynomial is 6.

Answer: 6 roots

Question 2:

The degree of the polynomial is 5.

Answer: 5 roots

8 0
4 years ago
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