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maw [93]
3 years ago
15

Candice cycles 2 kilometers during each trip to work. How many trips will Candice have to

Mathematics
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

2

Step-by-step explanation:

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4. 1/3(3y - 6) = 8 i need the answer to this please​
tiny-mole [99]

1/3 (3y - 6) = 8

distribute: y - 2 = 8

add 2 to both sides: y = 10

10

8 0
3 years ago
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Write in detail how you have used math in the real-world to solve a problem.
neonofarm [45]

Answer:

I went shopping once for ingredients of a cake, but i didn't know what my finale price would be. So i estimated what the total cost could be, then i took all the prices and added them up then divided the price by how many ingredients i got to find the average and it was pretty close to my estimate. So math can help when you go shopping. (Sorry if how i find my prices is weird, i kinda just stand in one spot for at least 5 - 8 mins trying to find my price)

Step-by-step explanation:

3 0
3 years ago
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The probability that a certain make of car will need repairs in the first seven months is 0.9. A dealer sells three such cars. W
aleksandr82 [10.1K]

Answer:

0.9990 = 99.90% probability that at least one of them will require repairs in the first seven months.

Step-by-step explanation:

For each car, there are only two possible outcomes. Either they will require repair in the first seven months, or they will not. The probability of a car requiring repair in the first seven months is independent of other cars. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a certain make of car will need repairs in the first seven months is 0.9.

This means that p = 0.9A dealer sells three such cars.

A dealer sells three such cars.

This means that n = 3

What is the probability that at least one of them will require repairs in the first seven months?

Either none will require repairs, or at least one will. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X > 0) = 1

We want P(X > 0). So

P(X > 0) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.9)^{0}.(0.1)^{3} = 0.001

Then

P(X > 0) = 1 - P(X = 0) = 1 - 0.001 = 0.9990

0.9990 = 99.90% probability that at least one of them will require repairs in the first seven months.

4 0
3 years ago
Convert 407 in base 8 to decimal​
Tems11 [23]

4\cdot8^2+0\cdot8^1+7\cdot8^0=256+7=263

407_8=263_{10}

5 0
3 years ago
Which other number is the same number of steps from 0 as -3?
vazorg [7]

Answer:

3

Step-by-step explanation:

The absolute value means spaces away from zero. -3 is 3 spaces away and 3 is also 3 spaces away. Hope this helps!

6 0
3 years ago
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