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mixer [17]
2 years ago
8

Guys please help me with question 1 , 2 and 3 pleaseeee

Mathematics
1 answer:
faust18 [17]2 years ago
4 0

Answer: 10 points, please!

Step-by-step explanation:


1. for the medium you want to find the number thats in the middle. so you have to write out all the numbers in order. then you step by step go to the middle and theres your medium.

0, 2, 2, 2, 3, 3, 3, 3, 3, 3, 5, 5, 6, 6, 7, 11

2, 2, 2, 3, 3, 3, 3, 3, 3, 5, 5, 6, 6, 7

2, 2, 3, 3, 3, 3, 3, 3, 5, 5, 6, 6,
2, 3, 3, 3, 3, 3, 3, 5, 5, 6,

3, 3, 3, 3, 3, 3, 5, 5,

3, 3, 3, 3, 3, 5,

3, 3, 3, 3,
3, 3,


The medium is 3.


2. for the mean you add all the numbers up and then divide based on how many numbers there are.

0 + 2 + 2 + 2 + 3 + 3 + 3 + 3 + 3 + 3 + 5 + 5 + 6 + 6 + 7 + 11 / 16

64/16

4

the average or mean is 4 which tells us that the average number of kids per houshold is 4. and none of the housholds have 4 children. we know this because of the data in the line plot.

the typical houshold size is either 3 or 4. the medium is 3 and the average or mean is 4.

10 points please

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3.3^(2x+1)-103^x+1=0 need value of x
photoshop1234 [79]

Answer:

The value of x is approximately -1.531.

Step-by-step explanation:

Let 3.3^{2\cdot x + 1}-103^{x+1} = 0, we proceed to solve this expression by algebraic means:

1) 3.3^{2\cdot x + 1}-103^{x+1} = 0  Given

2) 3.3^{2\cdot x}\cdot 3.3 -103^{x}\cdot 103 = 0 a^{b}\cdot a^{c} = a^{b+c}

3) (3.3^{x})^{2}\cdot 3.3 -\left[\left( \sqrt{103} \right)^{2}\right]^{x}\cdot 103 = 0 (a^{b})^{c} = a^{b\cdot c}

4) (3.3^{x})^{2}\cdot 3.3 - \left[\left(\sqrt{103}\right)^{x}\right]^{2}\cdot 103 = 0 (a^{b})^{c} = a^{b\cdot c}/Commutative property

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6) \left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\frac{103}{3.3} Existence of additive inverse/Modulative property/(a^{b})^{c} = a^{b\cdot c}

7) \log \left(\frac{3.3}{\sqrt{103}} \right)^{2\cdot x}=\log \frac{103}{3.3} Definition of logarithm.

8) 2\cdot x\cdot \log \left(\frac{3.3}{\sqrt{103}} \right)= \log \frac{103}{3.3}     \log_{b} a^{c} = c\cdot \log_{b} a

9) 2\cdot x \cdot [\log 3.3-\log \sqrt{103}] = \log 103 - \log 3.3      \log_{b} \frac{a}{d}

10) x\cdot (2\cdot \log 3.3-\log 103) = \log 103 - \log 3.3     \log_{b} a^{c} = c\cdot \log_{b} a/Associative property

11) x = \frac{\log 103-\log 3.3}{2\cdot \log 3.3-\log 103}   Existence of multiplicative inverse/Definition of division/Modulative property

12) x \approx -1.531  Result

The value of x is approximately -1.531.

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