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Anika [276]
2 years ago
7

A password is 4 characters long and must consist of 3 letters and one number. if letters cannot be repeated and the password mus

t end with a number, how many possibilities are there? a. 175,760 b. 158,184 c. 156,000 d. 140,400 please select the best answer from the choices provided a b c d
Mathematics
1 answer:
cestrela7 [59]2 years ago
4 0

We will see that there are 156,000 different combinations, so the correct option is C.

<h3>How many possibilities are there? </h3>

First, we need to find the selections, here we have:

  • First letter.
  • Second letter.
  • Third letter.
  • Number.

Now we need to find the number of options for each of these selections.

  • First letter. (26 options)
  • Second letter. (25 options, because we can't repeat letters)
  • Third letter. (24 options)
  • Number. (10 options).

We assumed that the number can be any integer from 0 to 9.

The total number of possibilities is equal to the product between the numbers of options, we will have:

P = 26*25*24*10 = 156,000

So, the correct option is C.

IF you want to learn more about combinations.

brainly.com/question/11732255

#SPJ4

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