Students : A B C D E F
3 of them (A, B, & C) must be seated together
options::
A B C D E F ..... D E F A B C ..... D A B C E F ..... D E A B C F
A B C D F E ..... D F E A B C ..... D A B C F E ..... D F A B C E
A B C E F D ..... E F D A B C ..... E A B C F D ..... E F A B C D
A B C E D F ..... E D F A B C ..... E A B C D F ..... E D A B C F
A B C F E D ..... F E D A B C ..... F A B C E D ..... F E A B C D
A B C F D E ..... F D E A B C ..... F A B C D E ..... F D A B C E
24 options
Answer:
$10 bill = 14 and $20 bill = 16.
Step-by-step explanation:
Given : A cashier has 30 bills, all of which are $10 or $20 bills. The total value of the money is $460.
To find : How many of each type of bill does the cashier have.
Solution : We have given that
A cashier has 30 bills
Let bill of $10 = x .
Bill of $20 = y .
Money of $10 = 10x .
Money of $20 = 20y.
Total bill
x + y = 30-------(1)
10x + 20y = 460-----(2)
On multiplying equation 1 by 10 and subtracting from equation 2.
10x + 20 y = 460
(-)10x +(-) 10 y = (-)300
______________
0 + 10 y = 160 .
On dividing by 10
y = 16 .
Plug y = 16 in equation 1
x + 16 = 30
On subtracting both sides by 16.
x = 30 - 16.
x = 14
Therefore, $10 bill = 14 and $20 bill = 16.
Sin(36)=a/16
16sin(36)=a
9.41=a
$15,000 * 0.8 = $12,000
$12,000 * 0.8 = $9,600
$9,600 * .08 = $7,680
