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VikaD [51]
2 years ago
8

15 men produce 500 watches in 15 working days. How long would it take 45 men to produce 500

Mathematics
2 answers:
Olin [163]2 years ago
8 0

(Assuming every single man has the same working rate.)

Solution 1 :

If there is 45 men working, there will be 45 : 15 = 3 times as much men.

So, the amount of time taken will be reduced by 3 times.
=> It will take 15 : 3 = 5 days for 45 men to produce 500 watches.

Solution 2 :

15 men produce 500 watches in 15 days -> If there is only 1 man, it will take 15 x 15 = 225 (days).

If there is 45 men, the amount of time will reduce by 45 times.

So, it will take 225 : 45 = 5 days for 45 men to produce 500 watches.

VMariaS [17]2 years ago
3 0

Answer:

It would take 45 men 5 days to make 500 watches.

Explanation.

for 15 men it takes 15 days.

but if you have 45 men. that is 3x the amount of men.

they will be able to make watches 3 times faster.

just believe me its the right answer.

Please Vote Me Brainliest. Thank You.

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A rectangular field is 75 yards wide and 105 yards long
nika2105 [10]

Answer:

width = 72 yards

length = 108 yards

Step-by-step explanation:

Given:

  • Width = 75 yards
  • Length = 105 yards

<u>Area of the field</u> with the given values:

\begin{aligned}\textsf{Area of a rectangle}&=\sf width \times length\\& = \sf 75 \times 105\\& = \sf 7875\:\: yd^2\end{aligned}

To maintain the <u>same perimeter</u>, but <u>change the area</u>, either:

  • decrease the width and increase the length by the same amount, or
  • increase the width and decrease the length by the same amount.

In geometry, length pertains to the <u>longest side</u> of the rectangle while width is the <u>shorter side</u>.  Therefore, we should choose:

  • decrease the <u>width</u> and increase the <u>length</u> by the <u>same amount</u>.

<u>Define the variables</u>:

  • Let x = the amount by which to decrease/increase the width and length.

Therefore:

\implies \sf width \times length < 7875\:\:yd^2

\implies (75-x)(105+x) < 7875

Solve the inequality:

\begin{aligned}(75-x)(105+x) & < 7875\\7875-30x-x^2 & < 7875\\-x^2-30x & < 0\\-x(x+30) & < 0\\x(x+30) & > 0\\\implies x & > 0 \:\: \textsf{ or }\:\:x < - 30\end{aligned}

Therefore, as distance is positive only and the maximum width is 75 yd (since we are subtracting from the original width):

\begin{cases}\textsf{width} = 75 - x\\\textsf{length} = 105 + x\end{cases}

\textsf{where } 0 < x < 75

Therefore, to find the width and length of another rectangular field that has the same perimeter but a smaller area than the first field, simply substitute a value of x from the restricted interval into the found expressions for width and length:

<u>Example 1</u>:

  • Let x = 3

⇒ Width = 75 - 3 = 72 yd

⇒ Length = 105 + 3 = 108 yd

⇒ Perimeter = 2(72 + 108) = 360 yd

⇒ Area = 72 × 108 = 7776 yd²

<u>Example 2</u>:

  • Let x = 74

⇒ Width = 75 - 74 = 1 yd

⇒ Length = 105 + 74 = 179 yd

⇒ Perimeter = 2(1 + 179) = 360 yd

⇒ Area = 1 × 179 = 179 yd²

4 0
1 year ago
Read 2 more answers
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V125BC [204]
32 bceach one is plus 3
5 0
4 years ago
Let see if this work
allochka39001 [22]

Answer:

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3 0
3 years ago
Point R is located at (1, 2) on a coordinate grid. Point S is located at (4, 5) on the same
Aleksandr-060686 [28]

Answer:

4.2 units

most likely answer choice B

Step-by-step explanation:

(1, 2) and (4, 5)

To find the distance between two points, we use the distance formula:

d = \sqrt{(x_{2}-x_1)^2 + (y_2-y_1)^2 }

Let's plug in what we know.

d = \sqrt{(4 - 1)^2 + (5 - 2)^2 }

Evaluate the parentheses.

d = \sqrt{(3)^2 + (3)^2 }

Evaluate the exponents.

d = \sqrt{(9) + (9) }

Add.

d=\sqrt{18}

Evaluate the radical.

d = 4.24

Round to the nearest tenth.

d = 4.2 units

*note: The answer choice is 4.6. I'm not sure if that is a typo on someone's end, but the distance between these two points is exactly 4.24264068712 units.

Hope this helps!

6 0
3 years ago
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alukav5142 [94]
7/8 x = 21
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