Answer:
pretty sure its 123
Step-by-step explanation:
Answer: The complete question is found in the attachment
Step-by-step explanation:
Law of large numbers: The probability of occurrence of an event becomes closer to the theoretical probability as the number of trials increases
P(an ace) = 1/6
= 0.1667
= 16.67%
a) In 600 rolls, the value will be close to 16.67. compared to 60 rolls
Greater than 20% interval doesn't include 16.67%. So, for more than 20% ace, 60 rolls is better.
b) More than 15% interval includes 16.67. So, it is better to roll 600 times
c) The interval between 15% and 20% include 16.67% and hence, 600 rolls is better
d) Larger number of trials is better to get exactly 16
So, 600 rolls is better
Answer:
a.) .95
b.) The expected number of baskets is 10.50.
c.) 1.7748
Step-by-step explanation:
a.) This is a binomial distribution as there are two possibilities: makes a free throw or doesn't. This means that you can use the binomial function on a calculator to figure out the answer. Use the binomial CDF function on a calculator and the number of trials=15, probability of success=.7, lower bound=0, upper bound=7. Once you have evaluated the answer, .0500, it will need to be subtracted from1, as you want everything not included in this section. The answer to part a is thus 1-.0500=.95.
b.) The expected value is calculated by taking the total number of shots and multiplying it by the probability of making the shot: 15×.7=10.5 shots.
c.) The standard deviation of a binomial distribution can be calculated by the formula
. Plugging in the numbers you get
=1.7748.
Havent done this in years but i think it would just be 12
So, we already know that one hive has a weight of 11.607kg and .204kg is add each week, so we add on .204kg times, w, representing weeks onto 11.607kg and our t is our total of weight of a hive with respect to weeks

So in this case our w is 7.5 weeks and now we evaluate t

Solve

Answer:
Hive's weight will increase by 1.53kg in 7.5 weeks to 13.137kg