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Inessa05 [86]
4 years ago
12

Someone please help!

Mathematics
1 answer:
pav-90 [236]4 years ago
7 0

We need to find an expression which will help Sara calculate the total weight of the truck.

By hypothesis, we know that x represents the number of cans in the truck. And each can weigh 14 ounces, so the total weight of the cans in the truck is 14*x = 14x.

Now in the truck, there's a total of 840 cans and bottles combined. And x is the number of cans. So 840 - x is the number of bottles. And since each bottle's weight is 70 ounces, the total weight of the bottles in the truck is 70*(840-x) = 70*840 - 70*x = 58800 - 70x.

Now to find the total weight, we add the weight of the cans to the weight of the bottle: 14x + 58800 - 70x = 58800-56x.

So the equation to find the total weight of the truck is:

58800-56x, in which x represents the number of cans in the truck.

Hope this helps! :)

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For the graph, what is a reasonable constraint so that the function is at least 200?​
Anastasy [175]

Answer:

0\leq x\leq 15

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one

<em>For the graph below, what should the domain be so that the function is at least 200?   graph of y equals minus 2 times the square of x plus 30 times x plus 200 </em>

My answer:

Given the above information, we have:

y=-2x^2+30x+200

To make  the function is at least 200, it means that:

y=-2x^2+30x+200 ≥ 200

<=> -2x^2+30x ≥ 0

<=> x(-2x+30) ≥ 0

This is the product of two numbers hence would be positive only if either both are positive or both are negative

  • Case I: Both positive

x ≥ 0 and  (-2x+30) ≥ 0

<=> 0 ≤ x ≤ 15

  • Case II: Both negative

Then we get

x\leq 0 and -2x+30\leq 0\\\\x\leq 0 and x\geq 15

This is inconsistent as a value cannot be less than 0 and greater than 15

=> our correct answer is0\leq x\leq 15

Hope it will find you well.

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3 years ago
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Answer:

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Answer:

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Answer: 65.1 (mg)

Step-by-step explanation:

y=190*e^{-a*t}\\\\Calculate\ a:\\\\t=33,y=95(mg)\\\\190*e^{-a*33}=95\\\\e^{-a*33}=0.5\\\\-a*33=ln(0.5)\\\\a=\dfrac{ln(\dfrac{1}{2}) }{-33} \\\\a=0,02100... \approx{0.021}\\\\If\ t=51\ h, y=190*e^{-0.02100*51}=65.09167...\approx{65.1}

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Vlad1618 [11]

Answer:

One-half squared is one-fourth.

Step-by-step explanation:

When you divide fractions, you multiply the first term by the reciprocal of the second term. In this example, instead of multiplying 1/2 by 1/4, you now multiply 1/2 by 4. Therefore, one half is equal to 2 fourths.

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