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enyata [817]
1 year ago
6

12.3 Write the first five terms of the sequence whose general term is

2B4" id="TexFormula1" title="a_{n}=3^{n}+4" alt="a_{n}=3^{n}+4" align="absmiddle" class="latex-formula"> .
Mathematics
1 answer:
weeeeeb [17]1 year ago
8 0

Answer:

7,13,31,85,247......

Step-by-step explanation:

a_n =3^n + 4

        \sf a_1=3^1 + 4 = 3 + 4 = 7\\\\a_2 = 3^2 + 4 = 9 + 4 = 13\\\\a_3 = 3^3 + 4 = 27 + 4 = 31\\\\a_4 = 3^4  + 4 = 81 + 4 = 85\\\\a_5 = 3^5 + 4 = 243 + 4 = 247

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5% of what number is 85?
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5% = 0.5

0.5n = 85

Divide by 0.5

0.5n = 85
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n = 170.

The number is 170.
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It is known that 50% of adult workers have a high school diploma. If a random sample of 8 adult workers is selected, what is the
son4ous [18]

Answer:

85.56% probability that less than 6 of them have a high school diploma

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have a high school diploma, or they do not. The probability of an adult having a high school diploma is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

50% of adult workers have a high school diploma.

This means that p = 0.5

If a random sample of 8 adult workers is selected, what is the probability that less than 6 of them have a high school diploma

This is P(X < 6) when n = 8.

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{8,0}.(0.5)^{0}.(0.5)^{8} = 0.0039

P(X = 1) = C_{8,1}.(0.5)^{1}.(0.5)^{7} = 0.0313

P(X = 2) = C_{8,2}.(0.5)^{2}.(0.5)^{6} = 0.1094

P(X = 3) = C_{8,3}.(0.5)^{3}.(0.5)^{5} = 0.2188

P(X = 4) = C_{8,4}.(0.5)^{4}.(0.5)^{4} = 0.2734

P(X = 5) = C_{8,5}.(0.5)^{5}.(0.5)^{3} = 0.2188

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0039 + 0.0313 + 0.1094 + 0.2188 + 0.2734 + 0.2188 = 0.8556

85.56% probability that less than 6 of them have a high school diploma

7 0
3 years ago
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