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enyata [817]
2 years ago
6

12.3 Write the first five terms of the sequence whose general term is

2B4" id="TexFormula1" title="a_{n}=3^{n}+4" alt="a_{n}=3^{n}+4" align="absmiddle" class="latex-formula"> .
Mathematics
1 answer:
weeeeeb [17]2 years ago
8 0

Answer:

7,13,31,85,247......

Step-by-step explanation:

a_n =3^n + 4

        \sf a_1=3^1 + 4 = 3 + 4 = 7\\\\a_2 = 3^2 + 4 = 9 + 4 = 13\\\\a_3 = 3^3 + 4 = 27 + 4 = 31\\\\a_4 = 3^4  + 4 = 81 + 4 = 85\\\\a_5 = 3^5 + 4 = 243 + 4 = 247

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point a has the coordinates(2,5) point B has the coordinates (6,17) how long is segment ab in simplified radical form
IRISSAK [1]

Answer:

4\sqrt{10}

Step-by-step explanation:

We have been given that point A has the coordinates(2,5) point B has the coordinates (6,17).

To find the length of segment AB we will use distance formula.

\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Upon substituting coordinates of point A and point B in distance formula we will get,

\text{Distance between point A and point B}=\sqrt{(6-2)^2+(17-5)^2}

\text{Distance between point A and point B}=\sqrt{(4)^2+(12)^2}

\text{Distance between point A and point B}=\sqrt{16+144}

\text{Distance between point A and point B}=\sqrt{160}

\text{Distance between point A and point B}=4\sqrt{10}

Therefore, the length of segment AB is 4\sqrt{10}.

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3 years ago
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Answer:

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substitute for x:

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Answer:

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Step-by-step explanation:

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