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natka813 [3]
3 years ago
7

What is the center and radius of the circle with the equation (x - 2)2 + (y - 7)2 = 49

Mathematics
2 answers:
Svetlanka [38]3 years ago
7 0

The equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - coordinates of a center

r - a radius

We have:

(x-2)^2+(y-7)^2=49

Answer:

The center: (2, 7)

The radius: r² = 49 → r = √49 → r = 7

Law Incorporation [45]3 years ago
6 0

(x - 2)² + (y - 7)² = 49

(x - 2)² + (y - 7)² = 7²

We can say that the center is the opposite of the shown numbers, so if we see -2 in x, the center is 2 and -7 in y, the center is 7

C(2, 7) and r = 7

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