Answer:
The binomial in expanded form is 
.
Step-by-step explanation:
The Binomial Theorem states that a binomial of the form 
can be expanded by using the following identity:
(1)
If we know that 
and 
, then the expanded form of the binomial is:
n/-5 - 9 = 2
move -9 to the other side
sign changes from -9 to 9
n/-5-9+9=2+9
n/-5=2+9
n/-5=11
multiply both sides by -5/1 to find n
(n/-5)(-5/1)=11(-5/1)
n=-55
answer: n=-55
X^2 = 3x + 5
x^2 - 3x - 5 = 0
a(alpha) and b(beta are roots
(x - a)(x - b) = 0
x^2 - (a+b)x + ab = 0
compare coefficients
a+b = 3
ab = -5
solving
(1/a^2 + 1/b^2)
= (a^2 + b^2)/(ab)^2
= (a^2 + 2ab + b^2 - 2ab)/(ab)^2
= [(a+b)^2 - 2ab]/(ab)^2
= [(3)^2 - 2(-5)]/(-5)^2 =...
prove
a^4 = 57a + 70
let x=a,
a^2 = 3a + 5
(a^2)^2 = (3a + 5)^2
a^4 = 9a^2 + 30a + 25
a^4 = 9(3a + 5) + 30a + 25
a^4 = 57a + 70
D) because you add six and multiply by 5
