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2 years ago

Help me simplify this radical

Mathematics

1 answer:

Lady_Fox [76]2 years ago

6 0

Answer:

5 $\sqrt{3}$ $b^{5}$

Step-by-step explanation:

$\sqrt{25}$ ×3 $b^{10}$

$\sqrt{5^2}$ ×3 $b^{10}$

$\sqrt{5^2} \sqrt{b^2} \sqrt{3}$

5 $b^{5} \sqrt{3}$

5 $\sqrt{3}$ $b^{5}$

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Step-by-step explanation:

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3 years ago

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3 years ago

PLS help<br> solve for x: -6(2x-5) = 18

Mashutka [201]

Hey!

$-6(2x-5) = 18$

Switch it around and it becomes:

$2x - 5 = 18 \div -6$

First find 18 ÷ -6

$18 \div -6 = -3$

Positive ÷ negative OR negative ÷ positive is always negative.

That leaves you with:

$2x - 5 = -3$

Switch that around and it becomes:

$-3 + 5 = 2x$

Find -3 + 5

$-3 + 5 = 2$

That leaves you with:

$2 = 2x$

Divide both sides by 2 to leave <em>x</em> alone

$\frac{2}{2} = \frac{2x}{2}$

$\framebox{x = 1}$

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3 years ago