4.5 (4-x)+36=202-2.5(3x+28)
45 (4-x)+360=2020-25(3x+28)
-45x+540=-75x+1320
-45x+540-540=-75x+1320-540
-45x=-75x+780
-45x+75x=-75x+780+75x
30x=780
30x/30= 780/30
x=26 the anser
Answer:
1) 0.4y + 20
2) 1.8h + 3
Step-by-step explanation:
1) 4(0.1y + 5) = 0.4y + 20
Multiply (4) to (0.1y) and then multiply (4) to (+5).
2) 0.6(3h + 5) = 1.8h + 3
Multiply (0.6) to (3h) and then multiply (0.6) to (+5).
Answer:
![\begin{aligned}\bullet\ &f(1)=800;f(n)=f(n-1)+900, \text{for $n\ge 2$}\\ \bullet\ & f(n)=900n-100\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cbullet%5C%20%26f%281%29%3D800%3Bf%28n%29%3Df%28n-1%29%2B900%2C%20%5Ctext%7Bfor%20%24n%5Cge%202%24%7D%5C%5C%20%5Cbullet%5C%20%26%20f%28n%29%3D900n-100%5Cend%7Baligned%7D)
Step-by-step explanation:
See attachment for the figure.
Using arithmetic sequence with a first term of 800 and a common difference of 900. The general form for such a sequence is given by,
an = a1 +d(n -1)
an = 800 +900(n -1) = 900n -100
If n is the function, this can be written as,
f(n) = 900n -100
When considered as a recursive relation, we find the first term is still 800:
f(1) = 800
and that each term is 900 more than the previous one:
f(n) = f(n-1) +900 . . . . for n ≥ 2
You need to consider that huge numbers of the different answer decisions are debasements of either of these structures, so you should look at them cautiously.
Simplify :
12+-5x+6x=4
combine like terms :
-5x+6x=1x
12+1x=4
solving :
12+1x=4
solving for variable ‘x’
move all terms containing x to the left, all other terms to the right, add ‘-12’ to each side of the equation
12+-12+1x=4+-12
combine like terms:
then divide each side
your answer : x=-8
Answer:The equation can be calculated by the following steps;
Step-by-step explanation: