Last term of the arithmetic progression 8,15,22 is 218. Findthe number of terms.
1 answer:
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For the units positions of all numbers we have:
From this we can conclude that total sum of these three numbers is 14. Number 1 we carry to next step. So we have:
For the tens positions of all numbers we have:
The extra number 1 on left side comes from the carry from last step. Similar to ones position we know that total sum is 11.
Now we insert x and z to find out y:
Now we need to find out the product of these three numbers:
From this we can conclude that total sum of these three numbers is 14. Number 1 we carry to next step. So we have:
For the tens positions of all numbers we have:
The extra number 1 on left side comes from the carry from last step. Similar to ones position we know that total sum is 11.
Now we insert x and z to find out y:
Now we need to find out the product of these three numbers: