Last term of the arithmetic progression 8,15,22 is 218. Findthe number of terms.

Mathematics

1 answer:

icang [17]3 years ago

7 0

Answer:

31 terms.

Step-by-step explanation:

218 = 8 + (n-1)7

210 = (n-1)7

30 + n-1

n = 31

There would be 31 terms in the given AP.

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Let A = {10, 20, 30, 40, 50, 60} and B = {10, 40, 60}. What is A ∩ B?

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This means common members {10,40,60}

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3 years ago

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Suppose you take a 15 question True or False quiz and you guess on every problem. You only get 3 correct. (a) What is the probab

lana66690 [7]

Answer:

0.648

No, that is not an unusually low number of correct guesses.

Step-by-step explanation:

Suppose you take a 15 question True or False quiz and you guess on every problem. You only get 3 correct. Then

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$q=1-p=1-0.2=0.8$ - o\incorrect.

The probability of getting 3 or fewer correct guesses is

$P(\text{3 or fewer})\\=P(0)+P(1)+P(2)+P(3)\\ \\=C^{15}_0p^0q^{15-0}+C^{15}_1p^1q^{15-1}+C^{15}_2p^2q^{15-2}+C^{15}_3p^0q^{15-3}\\ \\=1\cdot q^{15}+15pq^{14}+105p^2q^{13}+455p^3q^{12}\\ \\=(0.8)^{15}+15\cdot 0.2\cdot (0.8)^{14}+105\cdot (0.2)^2\cdot (0.8)^{13}+455\cdot (0.2)^3\cdot (0.8)^{13}\\ \\\approx 0.648$

Using the criteria that a number 3 is unusually low if P(3 or fewer) ≤ 0.05, we can state that 3 is not an unusually low number of correct guesses.

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3 years ago

Suppose that the scores, X, on a college entrance examination are normally distributed with a mean score of 560 and a standard d

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Answer:

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Step-by-step explanation:

The 33rd percentile corresponds to a score of 542.4. In order for a score to be within the top 67%, it must be above that value. The least integer above that value is 543.