Answer:
-3
Step-by-step explanation:
The length of a segment is
sqrt( ( y2-y1)^2 + (x2-x1) ^2) = 2 sqrt(10)
sqrt( ( a-4 - -1)^2 + (2a -4) ^2) = 2 sqrt(10)
sqrt( ( a-4 +1)^2 + (2a -4) ^2) = 2 sqrt(10)
Combine like terms
sqrt( ( a-3)^2 + (2a -4) ^2) = 2 sqrt(10)
Square each side
( a-3)^2 + (2a -4) ^2) = 4 *(10)
FOIL the left side
a^2 -6a +9 + 4a^2 -16a +16 = 40
Combine like terms
5a^2 -22a +25 = 40
Subtract 40 from each side
5a^2 -22a -15 =0
Factor
(a - 5) (5 a + 3) = 0
Using the zero product property
a-5 =0 5a +3 = 0
a = 5 5a = -3
a=5 a = -3/5
The product of the terms is
5 * -3/5 = -3
The compound inequality that represents the two following scenarios are:
- 65 < f ≤ 4
- 8 ≤ f ≤ 12
A compound inequality usually puts together two or more simple inequalities statements together.
Following the assumption from the given information that;
- a free single scoop cone = f
<h3>1.</h3>
The age group of individuals designated to receive the free single scoop cones is:
- people who are older than 65 i.e. > 65
- children that are 4 or under 4 i.e. ≤ 4
Thus, the compound inequality that is appropriate to express both conditions is:
<h3>
2.</h3>
- On Tuesdays, the least amount of flavors = 8
- The addition amount of extra flavors they can add = 4
Now, we can infer that the total amount of flavors = 8 + 4 = 12
Thus, the compound inequality that is appropriate to express both conditions is:
- Least amount of flavors ≤ f ≤ total amount of flavors
- 8 ≤ f ≤ 12
Therefore, we can conclude that the compound inequality that represents the two following scenarios are:
- 65 < f ≤ 4
- 8 ≤ f ≤ 12
Learn more about compound inequality here:
brainly.com/question/24540195?referrer=searchResults
Answer:
m = -2
Step-by-step explanation:
To find the slope of a line, use the equation:
m = y2 - y1 / x2 - x1
Then, substitute in values:
m = 54 - 58 / 2 - 0
m = -4 / 2
m = -2
Answer:
(11)(B) Simplify numeric and algebraic expressions using the laws of exponents, including integral ... Evaluate the expression for d = -2, d = 0, and d = 1.
Step-by-step explanation:
