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jeka94
3 years ago
8

Amy worked 16 hours more than Brayden last month. If Amy worked 8 hours for every 7 hours that Brayden worked, how many hours di

d they each work? (round answers to 1 decimal place) Amy worked hours Brayden worked hours
Mathematics
1 answer:
marishachu [46]3 years ago
8 0

Answer:

Amy worked for 128 hours while Brayden worked for 112 hours

Step-by-step explanation:

Given

Let A represents Amy and B represents Brayden

A = 16 + B ------(1)

A:B = 8:7------- (2)

Required

Find A and B;

Convert (2) to fractions

\frac{A}{B}  = \frac{8}{7}

Cross Multiply

7 * A = 8 * B

7A = 8B

Substitute A = 16 + B in the above expression

7(16 + B) = 8B

Open Bracket

7 * 16 + 7 * B = 8B

112 + 7B = 8B

Subtract 7B from both sides

112 + 7B - 7B = 8B - 7B

112 = B

B = 112

Recall that A = 16 + B

Hence, A = 16 + 112

A = 128

<em>This implies that Amy worked for 128 hours while Brayden worked for 112 hours</em>

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