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cestrela7 [59]
2 years ago
8

Can someone help me with this question? thank you!

Mathematics
1 answer:
Gwar [14]2 years ago
4 0

Answer:

152 in. squared

Step-by-step explanation:

Surface area = L×W + L×W+ 1/2 ×h ×b+ 1/2 × b×h + L×W

= 7×6 + 6×5+ 1/2×4×8 +1/2×4×8 +6×8

= 42+ 30 +16 +16 +48

=152 in. squared

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Can somebody help me please
Sergeu [11.5K]
Area = length x width

24 = (n-3) x 2
24 = 2n -6
2n = 30
n = 15

Length is 15-3 =12, width is 2
24 = 12 x 2
3 0
3 years ago
Read 2 more answers
What is 329,625 rounded to the place value of the underlined digit?
dexar [7]

Answer:

330,000

Step-by-step explanation:

if the underlined digit is 9, then the six rounds the 9 up to a 10, making the rounded number amount to 330,000.

4 0
3 years ago
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One number exceeds another by 26. the sum of the numbers is 58. what are the numbers
Gnom [1K]
First number = X

second number = x +26  ( exceeds means higher so add 26)

x + x+26 = 58

combine like terms:

2x + 26 = 58
 subtract 26 from each side:

2x = 58-26

2x = 32

divide both sides by 2:
x = 32/2
x = 16

first number is 16
second number = 16+26 = 42



5 0
3 years ago
Dan draws a circle with a radius of 8 inches. Question 1 Part A: What is the circumference of Dan's circle, inches? If needed, r
geniusboy [140]

Answer:

The circumference of Dan's circle is approximately 50.27 inches.

Step-by-step explanation:

The length of the circumference (s), measured in inches, is determined by the formula:

s = 2\pi\cdot r (1)

Where r is the radius, measured in inches.

If we know that r = 8\,in, then the length of the circumference is:

s = 2\pi\cdot (8\,in)

s \approx 50.27\,in

The circumference of Dan's circle is approximately 50.27 inches.

8 0
3 years ago
Find one value of x that is a solution to the equation:<br>(x^2– 8)^2 + x^2 – 8 = 20<br>x=​
Kipish [7]

Answer:

x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

Step-by-step explanation:

Solve for x:

-8 + x^2 + (x^2 - 8)^2 = 20

Expand out terms of the left hand side:

x^4 - 15 x^2 + 56 = 20

Subtract 20 from both sides:

x^4 - 15 x^2 + 36 = 0

Substitute y = x^2:

y^2 - 15 y + 36 = 0

The left hand side factors into a product with two terms:

(y - 12) (y - 3) = 0

Split into two equations:

y - 12 = 0 or y - 3 = 0

Add 12 to both sides:

y = 12 or y - 3 = 0

Substitute back for y = x^2:

x^2 = 12 or y - 3 = 0

Take the square root of both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y - 3 = 0

Add 3 to both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y = 3

Substitute back for y = x^2:

x = 2 sqrt(3) or x = -2 sqrt(3) or x^2 = 3

Take the square root of both sides:

Answer: x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

8 0
3 years ago
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