I think it would be the second graph
Let the number of large bookcases be x and number of small bookcases be y, then
Maximise P = 80x + 50y;
subkect to:
6x + 2y ≤ 24
x, y ≥ 2
The corner points are (2, 2), (2, 6), (3.333, 2)
For (2, 2): P = 80(2) + 50(2) = 160 + 100 = 260
For (2, 6): P = 80(2) + 50(6) = 160 + 300 = 460
For (3.333, 2): P = 80(3.333) + 50(2) = 266.67 + 100 = 366.67
Therefore, for maximum profit, he should produce 2 large bookcases and 6 small bookcases.
I believe the answer should be 77
The answer is a I'm pretty sure
Answer:
The factored form would be (8g + 7h)(2g - 5h)
Step-by-step explanation:
In order to find this, we need to use factors of 16g^2 in the front of the parenthesis. We also need to use factors of -35h^2 in the second side. Now we try these in the parenthesis and FOIL until we get an appropriate middle term.
