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andriy [413]
3 years ago
6

Find the distance between points 5,9 and (7,-7) using the distance formual

Mathematics
1 answer:
mart [117]3 years ago
5 0
========================================
Formula to find Distance:
========================================
\text{Distance = }  \sqrt{X2-X1)^2 + (Y2-Y1)^2}

========================================
Find Distance between (5, 9) and (7, -7):
========================================

X2 = 5, X1 = 7, Y2 = 9, Y1 = -7, therefore,

\text{Distance = }  \sqrt{(9+7)^2 + (5-7)^2}
\text{Distance = }  \sqrt{(16)^2 + (2)^2}
\text{Distance = }  \sqrt{256 + 4}
\text{Distance = }  \sqrt{260}
\text{Distance = } 16.12 \text{ units}

========================================
Answer: 16.12 units
========================================
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Linda had 84 fliers to post around town. Last week, she posted 1/3 of them. This week, she posted 2/7 of the remaining fliers. H
Jobisdone [24]

The remaining number of flires that Linda still not posted is 40.

According to the given question.

The total number of fliers Linda have = 84

Fraction of fliers Linda posted = 1/3

And, fraction of fliers Linda posted second time from the remaning fliers = 2/7

Now,

1/3 of 84 fliers = 1/3 × 84 = 28

So, the number of fliers are left with Linda after first posting = 84 - 28 = 56

Again she posted 2/7 fliers. The number of flires Linda posted second time is given by

⇒ 2/7 × 56 = 16

Thereore,  the number of fliers that Lindna still not posted  = 56 - 16 = 40

Hence, Linda still not posted 40 fliers.

Find out more information about fraction and remaining numbers here:

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4 0
1 year ago
PLS HELP WILL IVE BRAINLIST
pashok25 [27]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m
UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of \bar X Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

4 0
3 years ago
Are these two answers correct??
Damm [24]

Answer:

Yes

Step-by-step explanation:

7 0
3 years ago
10 points, doing this one again because I got a wrong answer last time but regardless thank you for trying to help​
Alik [6]

Hey ! there

Answer:

  • Value of missing side i.e. TE is <u>1</u><u>2</u><u> </u><u>feet</u>

Step-by-step explanation:

In this question we are provided with a <u>right</u><u> </u><u>angle </u><u>triangle</u> having <u>TS </u><u>-</u><u> </u><u>35</u><u> </u><u>ft </u><u>and</u><u> </u><u>SE </u><u>-</u><u> </u><u>37</u><u> </u><u>ft </u>. And we are asked to find the missing side that is <u>TE </u>using Pythagorean Theorem .

<u>Pythagorean Theorem :</u> -

According to Pythagorean Theorem sum of squares of perpendicular and base is equal to square of hypotenuse in a right angle triangle i.e.

  • H² = P² + B²

<u>Where </u><u>,</u>

  • H refers to <u>Hypotenuse</u>

  • P refers to <u>Perpendicular</u>

  • B refers to <u>Base</u>

<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>

In the given triangle ,

  • Base = <u>TE </u>

  • Perpendicular = <u>TS </u><u>(</u><u> </u><u>35</u><u> </u><u>feet </u><u>)</u>

  • Hypotenuse = <u>SE </u><u>(</u><u> </u><u>37</u><u> </u><u>feet </u><u>)</u>

Now applying Pythagorean Theorem :

\quad \longmapsto \qquad \:SE {}^{2}  = TS {}^{2}  + TE {}^{2}

Substituting values :

\quad \longmapsto \qquad \:37 {}^{2}  = 35 {}^{2}  + TE {}^{2}

Simplifying it ,

\quad \longmapsto \qquad \:1369 = 1225  + TE {}^{2}

Subtracting 1225 on both sides :

\quad \longmapsto \qquad \:1369 - 1225  = \cancel{1225}  + TE {}^{2}  -  \cancel{1225}

We get ,

\quad \longmapsto \qquad \:144 = TE {}^{2}

Applying square root to both sides :

\quad \longmapsto \qquad \ \sqrt{ 144} =  \sqrt{TE {}^{2}}

We get ,

\quad \longmapsto \qquad \:     \red{\underline{\boxed{\frak{TE  = 12 \: feet}}}} \quad \bigstar

  • <u>Henceforth</u><u> </u><u>,</u><u> </u><u>value </u><u>of </u><u>missing </u><u>side </u><u>is </u><em><u>1</u></em><em><u>2</u></em><em><u> </u></em><em><u>feet </u></em><em><u>.</u></em>

<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>

Now we are verifying our answer using Pythagorean Theorem . We know that according to Pythagorean Theorem ,

  • SE² = TS² + TE²

Substituting value of SE , TS and TE :

  • 37² = 35² + <u>1</u><u>2</u><u>²</u>

  • 1369 = 1225 + 144

  • 1369 = 1369

  • L.H.S = R.H.S

  • Hence , Verified .

<u>Therefore</u><u> </u><u>,</u><u> </u><u>our</u><u> answer</u><u> is</u><u> correct</u><u> </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
6 0
2 years ago
Read 2 more answers
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