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Nonamiya [84]
2 years ago
8

Can someone pls fill in the table asap!!!

Mathematics
1 answer:
Verizon [17]2 years ago
5 0

Answer:

_ I → _ I

o → 5

I → 11

2 → 17

3 → 23

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A. 2x = 5<br><br> What would be the answer I don’t know anyone help me before the 28th
Aleksandr [31]

Answer:

2.5

Step-by-step explanation:

4 0
3 years ago
What is the equation of the line passing through the point (4, 5) that is parallel to the line with the equation
Reptile [31]

Answer:

y=2x-3

Step-by-step explanation:

1. find the slope

6x-3y=21

-3y=-6x+21 divide both sides by -3

y=2x-7

slope is 2

2.y-5=2(x-4)

  y-5=2x-8

  y=2x-8+5

  y=2x-3

PARALLEL lines have the same slope

7 0
3 years ago
A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random
Yuliya22 [10]

Answer:

b) independent samples t-test

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

Step-by-step explanation:

The system of hypothesis on this case are:  

Null hypothesis: \mu_1 = \mu_2  

Alternative hypothesis: \mu_1 \neq \mu_2  

Or equivalently:  

Null hypothesis: \mu_1 - \mu_2 = 0  

Alternative hypothesis: \mu_1 -\mu_2\neq 0  

Our notation on this case :  

n_1 =5 represent the sample size for group 1  

n_2 =5 represent the sample size for group 2  

We can calculate the mean and deviation for eaach group with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X_1 =5.92 represent the sample mean for the group 1  

\bar X_2 =5.74 represent the sample mean for the group 2  

s_1=1.88 represent the sample standard deviation for group 1  

s_2=1.81 represent the sample standard deviation for group 2  

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:  

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}  

And now we can calculate the statistic:  

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

The degrees of freedom are given by:  

df=5+5-2=8

And now we can calculate the p value using the altenative hypothesis:  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

7 0
3 years ago
ΔEʹFʹGʹ is a dilation of ΔEFG with the origin as the center of dilation.
vekshin1
  the answer a is 6 and b is 2

7 0
3 years ago
Ppppppplllllzzzzzzzzzz huuuuuuurrrrrryyyyyyyyyyyy What is missing from the frequency chart below?
Alekssandra [29.7K]

Answer: A

Step-by-step explanation:

A

I think, i looked it up, im sorry if im wrong. I tried.

7 0
3 years ago
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