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max2010maxim [7]
2 years ago
12

5. Find the largest difference between a 3-digit number and a 2-digit number. ​

Mathematics
1 answer:
Kay [80]2 years ago
3 0

Answer:

989

Step-by-step explanation:

The largest difference could be possible between Largest 3 digit number and smaller two digit number

I.e,

999-10=989

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Simplify xi(I-7i) ^2
topjm [15]
Note what i actually represents.
i is the very basis of a whole new level of counting. When finding discriminants, we often say that a quadratic has no real roots if the discriminant is 0. Needless to say, there are roots, they are just imaginary.

\sqrt{-1}, in real terms, is non-existent. That is, there are no numbers in the real number system that when multiplied by itself produces a result of -1. This is what i unit represents.

Let's tackle this problem in smaller steps.
Let's first expand our brackets.

(i - 7i)² = (-6i)² = 36i²
Now, let's distribute the xi.

xi(i - 7i)² = xi(36i²) = 36xi³ = -36x\sqrt{-1} = -36xi
8 0
3 years ago
Read 2 more answers
Please help 18 points.!<br> I need to know what goes in the three boxes.
timofeeve [1]

Answer:

The first box is 1 then 2 / 8 for the last

Step-by-step explanation:

It's:

1

-

8

Then

2

_

8

Because 4 x 2 = 8 for the denominator

and 1 x 2 = 2 for the numerator

6 0
3 years ago
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Can u pls go sub :)))))
nlexa [21]

Answer

Step-by-step explanation:

Done!

5 0
3 years ago
Find the coordinate of the midpoint of the segment formed by the given points: (7, 11) and (3, -5)
sveta [45]

Answer:

MP = (5,3)

Step-by-step explanation:

MP= (\frac{x_1+x_2}{2}) (\frac{y_1+y_2}{2} )\\MP= (\frac{7+3}{2}) (\frac{11+-5}{2} )\\MP= (\frac{10}{2}) (\frac{6}{2} )\\MP= (5,3)

8 0
3 years ago
One-hour carbon monoxide concentrations in 43 air samples from a section of a city showed an average of 11.6 ppm and a standard
DENIUS [597]
The test statistic for difference between two means is given by:

z= \frac{(\bar{x}_1-\bar{x}_2)-(\mu_1-\mu_2)}{ \sqrt{ \frac{\sigma^2_1}{n_1} +\frac{\sigma^2_2}{n_2}} }

Thus, the appropriate test statistic is given by:

z= \frac{(11.6-6.4)-2}{ \sqrt{ \frac{(7.08)^2}{43} +\frac{(6.94)^2}{19}} } \\  \\ = \frac{5.2-2}{ \sqrt{ \frac{50.1264}{43} + \frac{48.1636}{19} } } = \frac{3.2}{ \sqrt{1.1657+2.5349} }  \\  \\ = \frac{3.2}{ \sqrt{3.7007} }  = \frac{3.2}{1.9237} =1.66

At 10% level of significance, the rejection region is given by

z\geq z_0

where: z_0 for 10% level of significance is 1.65

Since z = 1.66 > z_0=1.65, we reject the null hypothesis, which means that <span>the traffic control strategy does not reduce carbon monoxide concentrations by at least 2 ppm.</span>
3 0
3 years ago
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