Freakishly Nyah but V gdbsbsbs
Answer: A =350 (1.05)^t
Step-by-step explanation:
Hi, to answer this question we have to apply an exponential growth function:
A = P (1 + r) t
Where:
p = original population
r = growing rate (decimal form; 5/100=0.05)
t= years
A = population after t years
Replacing with the values given:
A = 350 (1+0.05)^t
A =350 (1.05)^t
Feel free to ask for more if needed or if you did not understand something.
Answer:
![3 + \frac{1}{2\sqrt{3} } + \frac{1}{5\sqrt[5]{81} }](https://tex.z-dn.net/?f=3%20%2B%20%5Cfrac%7B1%7D%7B2%5Csqrt%7B3%7D%20%7D%20%2B%20%5Cfrac%7B1%7D%7B5%5Csqrt%5B5%5D%7B81%7D%20%7D)
Step-by-step explanation:
Just to make it easier to see,
and
This way we could more easily use the power rule of derivatives.
So if f(x) =
then f'(x) will be as follows.
f'(x) = ![x^{1} +\frac{1}{2} x^{-\frac{1}{2} } +\frac{1}{5} x^{-\frac{4}{5} } = x +\frac{1}{2x^{\frac{1}{2} }} +\frac{1}{ 5x^{\frac{4}{5} }} = x +\frac{1}{2\sqrt{x}} +\frac{1}{ 5\sqrt[5]{x^4} }](https://tex.z-dn.net/?f=x%5E%7B1%7D%20%2B%5Cfrac%7B1%7D%7B2%7D%20x%5E%7B-%5Cfrac%7B1%7D%7B2%7D%20%7D%20%2B%5Cfrac%7B1%7D%7B5%7D%20x%5E%7B-%5Cfrac%7B4%7D%7B5%7D%20%7D%20%3D%20x%20%2B%5Cfrac%7B1%7D%7B2x%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%7D%20%2B%5Cfrac%7B1%7D%7B%205x%5E%7B%5Cfrac%7B4%7D%7B5%7D%20%7D%7D%20%3D%20x%20%2B%5Cfrac%7B1%7D%7B2%5Csqrt%7Bx%7D%7D%20%2B%5Cfrac%7B1%7D%7B%205%5Csqrt%5B5%5D%7Bx%5E4%7D%20%7D)
to find f'(3) just plug 3 into f'(x) so ![3 + \frac{1}{2\sqrt{3} } + \frac{1}{5\sqrt[5]{81} }](https://tex.z-dn.net/?f=3%20%2B%20%5Cfrac%7B1%7D%7B2%5Csqrt%7B3%7D%20%7D%20%2B%20%5Cfrac%7B1%7D%7B5%5Csqrt%5B5%5D%7B81%7D%20%7D)
Answer:
-2 for BOTH
Step-by-step explanation:
Since 11 is 2 below 3
and 19 as well
the answer is below zero
this is a negative number
-2
Answer:
spinner will stop on red: 1/3
cube will show a two: 1/6 of a chanes