3 1/3= 10/3
2 1/3= 7/3
7/3 + 10/3= 17/3
17/3 (2)+ 34/3
34/3= 11 1/3
final answer = 11 1/3
<span>33 =1, 3, 11, 33
75</span><span>=1, 3, 5, 15, 25, 75</span>
Average (mean) = (sum of all the data) / (# of data)
sum of all the data = (average)(# of data)
Thus for 100 students with an average of 93,
sum of all data = (93)(100) = 9300
and for 300 students with an average of 75,
sum of all data = (75)(300) = 22500
Therefore you would expect the overall average to be
(9300 + 22500) / (100 + 300) = 79.5 %
Now if there are x # of advanced students and y # of regular students, then
x + y = 90 (total # of students) and 93x + 75y = 87(x + y) (overall average)
The second equation can be simplified to x - 2y = 0
Subtracting the two equations yields
x = 60 and y = 90
Therefore you would need 60 advanced and 30 regular students.
The second one is the best answer in my opinion i'm not sure.
