If you have 8 yellow balloons for every 12 blue balloons, then if you have 20 balloons in total, 8 out of 20 of those balloons will be yellow. Then you can set up this ratio:
Then, you can use either cross multiplication or multiply the numerator and denominator by the same number to help solve for x. Personally, I prefer cross multiplication, so that's what I'll show you here:
Finally, solve for x:
If you had 100 balloons, you will have
40 yellow balloons.
Hope this helps!!
Answer:
sum of terms: 55550
Explanation:
Here the number of terms:
1100 ÷ 11 = 100
Using the Formula:
Answer:
X= -5
Step-by-step explanation:
- You must move all constants to one side of the equation (one side of the equal sign) and away from 2x. To do so, you must do the inverse operation, which would be subtraction in this case because 3 is a positive number. (Inverse of addition is subtraction, Inverse of subtraction is addition, Inverse of multiplication is division, and inverse of division is multiplication) If you squish a constant and variable together (2x) it means multiplication.
- What you must do to one side, you must do to the other. So, since you subtracted 3 from the 3, you must subtract 3 from -7, too(subtracting from a negative is just addition- but you keep the negative sign). Once this is done, your equation will be 2x=-10
- Now, you must do the inverse operation to 2x to separate the 2. The inverse operation will be division. So, you divide both sides by 2. 2x divided by 2 will give you x. -10 divided by 2 will give you -5. (When you divided negative and positive numbers, the signs are different, meaning it's negative. If they had the same sign, it would be positive.)
- Therefore, your answer is x= -5
Hope I helped! :)
Sorry about the whole dang essay lol
Answer:
2
Offmind's Step-by-step explanation:
The Mode of a data set (<em>line plot in this case</em>) is the number which occurs most often. The line plot here shows the most x's on the number 2 than any other number so the mode is in fact, 2.
Bonus Fact: In another case, if there had been two numbers with the same amount of x's then those would both be considered the mode!
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Thanks!
-<em>Offmind</em>
