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emmainna [20.7K]
2 years ago
10

Simplify the expression. Write your answer as a power.

Mathematics
2 answers:
Masja [62]2 years ago
4 0

Answer:

this is your answer

{9}^{4}

il63 [147K]2 years ago
4 0
<h3>Answer:</h3>

\large{\sf \boxed{(\sf -3)^8}}

<h3>Explanation:</h3>

\rightarrow \sf ((-3)^2)^4

apply exponent rule: \sf \bf \left(a^b\right)^c=a^{bc}

\rightarrow \sf (-3)^8

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paloma eats 2/8 of an apple in the morning and 3/8 more in the afternoon. how much of an apple did she eat in total
marishachu [46]

Step-by-step explanation:

in this problem, we are solving for the amount of apple that Paloma eats

1. she ate 2/8 of a complete apple -hence the will be a remainder, we will find  

  that remainder

2. she also ate 3/8 of the remainder for lunch

3. we then proceed to calculate all apple she ate in total

1. \frac{2}{8} *1= \frac{1}{4} \\\\1-\frac{1}{4}= \frac{4-1}{4}  = \frac{3}{4}

2 she ate 3/8 of the remaining 3/4 apple

1. \frac{3}{8} *\frac{3}{4} = \frac{9}{32}

3. in  total she ate 1/4+ 9/32

\frac{1}{4} +\frac{9}{32} = \frac{8+9}{32} = \frac{17}{32}

6 0
4 years ago
Find the exact value of tan 67.5° trig
nataly862011 [7]

Answer: 1 + \sqrt{x} 2

5 0
3 years ago
The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and
kykrilka [37]

Answer:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

<u>15                       7.50                                 7.50  </u>

<u>∑                                                               17.0281</u>

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

8 0
3 years ago
During science class, Jack, Jeff, and Jill measure the length of their bean sprouts. Jeff’s sprout is 0.9 times the length of Ja
yKpoI14uk [10]

Answer:

Jill's is the longest.

if jeffs is 0.9 times the length of jacks, his is lesser than jacks. e.g. 2×0.9=1.8. Jeff's will always be shorter. since we know Jacks is over 1, Jill's will always be taller because 2×1.08=2.16 or Jill's length.

8 0
2 years ago
Subtract from both sides -6- (8.4) =1.2x +8.4 - (8.4)​
emmainna [20.7K]

Answer:

the value of x will be -12.....

8 0
3 years ago
Read 2 more answers
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