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emmainna [20.7K]
2 years ago
10

Simplify the expression. Write your answer as a power.

Mathematics
2 answers:
Masja [62]2 years ago
4 0

Answer:

this is your answer

{9}^{4}

il63 [147K]2 years ago
4 0
<h3>Answer:</h3>

\large{\sf \boxed{(\sf -3)^8}}

<h3>Explanation:</h3>

\rightarrow \sf ((-3)^2)^4

apply exponent rule: \sf \bf \left(a^b\right)^c=a^{bc}

\rightarrow \sf (-3)^8

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Aleks [24]

Answer:

A. 576 in (1728/3)

B. 1152^2 in (576x2)

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D. 576^2 ft (6912/12)

6 0
3 years ago
Malin and Shawn begin with the same number, t. Malin subtracts 6 from t and then divides the result by 6. Shawn adds 7 to t and
uysha [10]
T

adds 6
t-6

divides by 6
(t-6)/6



shawn
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theyare equal


(t-6)/6=(7+t)/7
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7 0
3 years ago
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Andrej [43]

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1, 2, and 5

Step-by-step explanation:

5 0
3 years ago
A storage company must design a large rectangular container with a square base. The volume is 6750ft3. The material for the top
GuDViN [60]
Ответ 163.54
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4 0
3 years ago
. Given that O is the centre of the following circle, find the values of the unknowns.​
alex41 [277]

Given:

Radius of circle is 13 cm

Height of triangle is 5 cm

To find:

Value of 'a' and 'b'

Steps:

To find value of 'a', we will use Pythagoras theorem as the triangle is a right angle triangle,

A² + B² = C²

a^{2} + 5^{2} = 13^{2}

a^{2} + 25 = 169

a^{2} = 169 - 25

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a = 12

Now to find the value of 'b', i will use law of cosine,

c=\sqrt{a^{2}+b^{2}-2ab(cos\beta ) }

12 = \sqrt{13^{2}+5^{2}-2(5)(13)(cos\beta )}\\12=\sqrt{169 + 25-130(cos\beta )}\\12=\sqrt{194-130(cos\beta )}\\144 = 194 - 130(cos\beta )\\50 = 130(cos\beta )\\cos\beta =   0.3846\\\beta  = cos^{-1}(0.3846)\\\beta = 67.38

Therefore, the values of 'a' and 'b' is 12 and 67.38 respectively

Happy to help :)

If u need any help feel free to ask

3 0
3 years ago
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